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laila [671]
4 years ago
15

If a rock is skipped into a lake at 24 m/s2, with that what force was the rock thrown if it was 1.75kg?

Physics
1 answer:
erma4kov [3.2K]4 years ago
6 0

Answer: f= M×A

1.75kg×24= 42N

Explanation:

Because to find force you do Mass times acceleration so I did 1.75 kg times 24 would equal 42 Newtons!

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Sally is trying to lift a heavy box, but is not strong enough to lift it.  Would the force that she is applying to the box be an
mestny [16]
If you give it unbalanced force it would go up and if you can't give it enough it will stay a balanced force
 
3 0
3 years ago
Water at 20 C flows through a 5-cm-diameter pipe that has a 180 vertical bend, as in Fig. P3.43. The total length of pipe betwee
Nataliya [291]

Answer:

F = 749 [N]

Explanation:

We must give full information on this problem, as well as the question that needs to be resolved.

Water at 20°C flows through a 5-cm-diameter pipe that has a 180° vertical bend. The total length of pipe between flanges 1 and 2 is 75 cm. When the weight flow rate is 230 N/s,

P1=165kPa

and

P2=134kPa

Neglecting pipe weight, determine the total force that the flanges must withstand for this flow.

We must make a U-shaped body diagram of the pipe in order to visualize the forces acting according to the pressures and the area of the pipe.

Then by means of the second law of motion of Newton, which says that the sum of the forces must be equal to the product of mass times acceleration, we can find the force Fp

Let us remember that pressure is defined as the divided force over the area, therefore:

F = P *A

where:

P = pressure

A = area

The product of the mass by acceleration, is equal to the product of the speed of the fluid by the mass flow, since we know the weight of the fluid we can find its mass flow.

W_{flow}=230[N/s]\\W_{flow} =g*m_{flow}\\m_{flow} = W_{flow} / g\\m_{flow} = 230/9.81\\m_{flow}= 23.45[kg/s]

In the function of the mass flow, we can find the velocity of the fluid, as we also know the diameter of the pipe

m_{flow} = density*v*A\\where\\density = 1000[kg/m^{3}]\\ v= velocity[m/s]\\A = area [m^{2}]\\v=\frac{m_{flow}}{density*A} \\v=\frac{23.45}{1000*\frac{\pi}{4}*(5*10^{-2})^{2} } \\v= 11.94 [m/s]

We know that the atmospheric pressure is equal to:

P_{atm} = 101.325[kpa]

The value of the pipe area is calculated for a circular section

A = \frac{\pi}{4} * (0.05)^{2}\\ A = 0.00196[m^{2} ]

The resultant force is 749 [N]

The solution of the equations and the free body diagram can be seen in the attached picture.

3 0
3 years ago
Graph the following data on the graph, then use the graph to determine the half-life of this isotope.
Harlamova29_29 [7]

Answer:

4, 56

Explanation:

Hope this helped!

7 0
3 years ago
Explain how the distance to a lightning bolt (Fig. CQ17.5) can be determined by counting the seconds between the flash and the s
Sonbull [250]

The distance to a lightning bolt can be determined by counting the seconds between the flash and the sound of thunder due to the speed of light is greater than the speed of sound

We must consider that the speed of light (3.00× 10⁸ m/s) is greater than the speed of sound (340 m/s), this is why we can first see the lightning and after seeing it we can hear it.

In order to calculate the distance we must count the time since the lightning bolt and use the speed of sound, applying the following formula:

x = v * t

Where:

  • x = distance
  • t = time
  • v = velocity

<h3>What is velocity?</h3>

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

Learn more about velocity at: brainly.com/question/80295?source=archive

#SPJ4

7 0
2 years ago
A car of mass 1800 kg collides with a truck of mass 5200 kg, and just after the collision the car and truck slide along, stuck t
kupik [55]

Explanation:

Elastic collision is said to occur if the total kinetic energy is not conserved and if there is a rebound after collision

Step one

Analysis of the problem

Immediately after impact the car's velocity was zero making it a perfect elastic collision

Step two

Given

Mass of car M1=1800kg

Mass of truck M2=5200kg

Initial velocity of Car U1=44m/s

Initial velocity of truck U2=21m/s

Final velocity of car V1= 0m/s

Final velocity of truck V2=20m/s

Step three

According to the principle of conservation of momentum

Total momentum before collision

=M1U1+M2U2

Total momentum after impact

=M1V1+M2V2

M1U1+M2U2 =M1V1+M2V2

Substituting our data into the expression we have 1500*44+5800*21=1500*0+5800*20

=66000+1218000=11600

1284000=11600

From the solution the momentum before impact is 1284000Ns

Momentum after impact is 11600Ns

This is indicating that after impact there was loss in momentum as a result of the car having a velocity of zero

8 0
4 years ago
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