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stepladder [879]
3 years ago
12

Sally is trying to lift a heavy box, but is not strong enough to lift it.  Would the force that she is applying to the box be an

example of an unbalanced force or a balanced force?  Why?
Physics
1 answer:
mestny [16]3 years ago
3 0
If you give it unbalanced force it would go up and if you can't give it enough it will stay a balanced force
 
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Yep it is. Defiantly the circulatory system
6 0
3 years ago
How much would you have to shrink a baseball to a black hole?
Vesna [10]

The Schwarzchild radius is . . . <em>R = 2GM/c²  .</em>

Just like you, I'm not completely sure what that means.  But it DOES use the mass of a black hole to calculate a radius associated with it, so with 15 Brainly points at stake, it seems like a good-enough formula to use for an answer.

Before I proceed, I really should ask you whether you're talking a softball or a hardball, but again . . . . .

So R = 2GM/c²

G = the  gravitational constant = 6.67 x 10⁻¹¹ N-m²/kg²

M = mass of the baseball = 145 grams = 0.145 kg

c = speed of light = 3 x 10⁸ m/s

R = 2 (6.67 x 10⁻¹¹ m³/kg-s²) (0.145 kg) / (3 x 10⁸ m/s)²

R = (2 x 6.67 x 10⁻¹¹ x 0.145 / 9 x 10¹⁶) (m³-kg-s² / kg-s²-m²)

R = ( 1.9343 x 10⁻¹¹ / 9 x 10¹⁶) (m³-kg-s²/m²-kg-s²)

R = (0.2149 x 10⁻²⁷) meter

<em>R = 2.149 x 10⁻²⁸ meter</em>

For reference: The radius of a Hydrogen atom is 1.2 x 10⁻¹⁰ meter.

So in order to make a black hole out of a baseball, you have to crunch the baseball down to around  0.000000000000000001791 the size of a Hydrogen atom.

Would that be a problem for you ?

3 0
3 years ago
What is the magnitude of component of a vector in<br>right angle to itself, ?​
AlexFokin [52]

Yes, but it's a null vector .So,no vector can have a component at right angle to itself unless it is a zero vector.

5 0
4 years ago
Two small plastic spheres are given positive electrical charges. When they are 16.0 cm apart, the repulsive force between them h
Drupady [299]

Answer:

q = 7.542 x 10⁻⁷ C = 754.2 nC

Explanation:

The Coulomb's Law gives the magnitude of the force of attraction or repulsion between two charges:

F = kq₁q₂/r²

where,

F = Force of attraction or repulsion = 0.2 N

k = Coulomb's Constant = 9 x 10⁹ N m²/C²

r = distance between charges = 16 cm = 0.16 m

q₁ = magnitude of 1st charge

q₂ = magnitude of 2nd charge

Since, both charges are said to be equal here.

q₁ = q₂ = q

Therefore,

0.2 N = (9 x 10⁹ N m²/C²)q²/(0.16 m)²

(0.2 N)(0.16 m)²/(9 x 10⁹ N m²/C²) = q²

q = √(5.88 x 10⁻¹³ C²)

<u>q = 7.542 x 10⁻⁷ C = 754.2 nC</u>

7 0
3 years ago
Scientists would like to learn more about the seismic activity that occurs on Earth’s surface. They are set to take a journey to
Ludmilka [50]

Answer:

the questions they could ask would be:

how much will the temperature change?

how much pressure will there be?

how durable does the equipment need to be?

how do we know if we will run into a water pocket or a magma pocket?

Explanation:

3 0
3 years ago
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