1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SIZIF [17.4K]
3 years ago
9

In doing a load of clothes, a clothes dryer uses 15 A of current at 240 V for 55 min. A personal computer, in contrast, uses 2.7

A of current at 120 V. With the energy used by the clothes dryer, how long (in hours) could you use this computer to "surf" the internet?
Physics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

Available usage time for the computer = 10.185 hrs

Explanation:

for the dryer;

I = 15 A,    V=240 V  ,  t= 55min,

convert time from min to sec. t = 55*60 =3300 sec

Energy = IVt

Energy = 15*240*3300

Energy = 11,880,000 J

            =11,800 KJ

using the energy for the clothes dryer to calculate for the time spent on the computer,

Energy = IVt

for the computer;

I = 2.7A    V=120V , t=?

t=\frac{energy}{IV}

t=\frac{11,800,000}{2.7*120}

t=36,666.7sec

convert this value to hour by dividing by 3600

t=\frac{36,666.7}{3600} \\t=10.185hrs

You might be interested in
75 POINTS!!!!! Please help me! I need the correct answer! This is my second time posting this cause no one answered.
son4ous [18]
According to the article "Nuclear shapes" by Renee Lucas the nucleus's shape is mainly modified by vibrational and rotational features happening within the cell. According to the article if i read correctly "near closed shells spherical shapes prevail, while between closed shells the large number of valence nucleons in orbit with large particle angular momentum leads to nuclei with large deformations leading them to not only maintain its shape but also alloying it to work.
6 0
3 years ago
Read 2 more answers
A thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 10° F. Af
vekshin1

Answer:

T=51.64^\circ F

t=180.10s

Explanation:

The Newton's law in this case is:

T(t)=T_m+Ce^{kt}

Here, T_m is the air temperture, C and k are constants.

We have

70^\circ F in t=0

So:

T(0)=70^\circ F\\T(0)=10^\circ F+Ce^{k(0)}\\70^\circ F=10^\circ F+C\\C=70^\circ F-10^\circ F=60^\circ F

And we have 60^\circ F in t=30 s, So:

T(30)=60^\circ F\\T(30)=10^\circ F+(60^\circ F)e^{k(30)}\\60^\circ F=10^\circ F+(60^\circ F)e^{k(30)}\\50^\circ F=(60^\circ F)e^{k(30)}\\e^{k(30)}=\frac{50^\circ F}{60^\circ F}\\(30)k=ln(\frac{50}{60})\\k=\frac{ln(\frac{50}{60})}{30}=-0.0061

Now, we have:

T=10^\circ F+(60^\circ F)e^{-0.0061t}(1)

Applying (1) for t=1 min=60s:

T=10^\circ F+(60^\circ F)e^{-0.0061*60}\\T=10^\circ F+(60^\circ F)0.694\\T=10^\circ F+41.64^\circ F\\T=51.64^\circ F

Applying (1) for T=30^\circ F:

30^\circ F=10^\circ F+(60^\circ F)e^{-0.0061t}\\30^\circ F-10^\circ F=(60^\circ F)e^{-0.0061t}\\-0.0061t=ln(\frac{20}{60})\\t=\frac{ln(\frac{20}{60})}{-0.0061}=180.10s

8 0
3 years ago
Answer this please nowww
Viefleur [7K]
(3) The frictional force exerted by the floor on the box
4 0
3 years ago
You push your friend, whose mass is 54kg, down a hill so she can go sledding. Her acceleration is 3m/s2. Calculate the amount of
Alecsey [184]

Answer:

18 newtons

Explanation:

Divide weight by speed

3 0
3 years ago
1. A 1.5 kg ball moves in a circle that is 0.5 m in radius at a speed of 5.1 m/s.
kolezko [41]

Answer: a= 52.02 m/s²

Fc= 78.03 N

Explanation: Solution attached:

3 0
3 years ago
Other questions:
  • Ice-skater slides toward a sled sitting on the ice and hits it. The skater exerts a 12.6 N force on the sled at an angle of 15.3
    9·1 answer
  • Neil studied how a pulley helps move an object. Neil tied a rope to an object with a mass of 10 kilograms (kg) and attached it t
    15·1 answer
  • What feature of a chemical equation represents the law of conservation of matter?
    12·2 answers
  • A bat hits a 0.150 kg baseball for
    11·1 answer
  • Who knows the egg drop challenge
    13·1 answer
  • The sound of a tuba is very low. Why?
    14·1 answer
  • 11 cm/s2 is an example of<br> 30 m/s northwest is an example of
    6·1 answer
  • weight of Ali is 500andN.he is standing on the ground with an area of 0.025 m^2 area .we can find pressure under his feet. what
    10·1 answer
  • Why we don’t feel atmospheric pressure?
    15·2 answers
  • the fireman wishes to direct the flow of water from his hose to the fire at b. determine two possible angles u1 and u2 at which
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!