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SIZIF [17.4K]
3 years ago
9

In doing a load of clothes, a clothes dryer uses 15 A of current at 240 V for 55 min. A personal computer, in contrast, uses 2.7

A of current at 120 V. With the energy used by the clothes dryer, how long (in hours) could you use this computer to "surf" the internet?
Physics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

Available usage time for the computer = 10.185 hrs

Explanation:

for the dryer;

I = 15 A,    V=240 V  ,  t= 55min,

convert time from min to sec. t = 55*60 =3300 sec

Energy = IVt

Energy = 15*240*3300

Energy = 11,880,000 J

            =11,800 KJ

using the energy for the clothes dryer to calculate for the time spent on the computer,

Energy = IVt

for the computer;

I = 2.7A    V=120V , t=?

t=\frac{energy}{IV}

t=\frac{11,800,000}{2.7*120}

t=36,666.7sec

convert this value to hour by dividing by 3600

t=\frac{36,666.7}{3600} \\t=10.185hrs

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Akimi4 [234]

The acceleration exerted by the object of mass 10 kg is \mathbf{1} m / \boldsymbol{s}^{2}

Answer: Option A

<u>Explanation:</u>

According to Newton’s second law of motion, any external force acting on a body will be directly proportional to the mass of the body as well as acceleration exerted by the body. So, the net external force acting on any object will be equal to the product of mass of the object with acceleration exerted by the object. Thus,

                  Force = Mass \times Acceleration

So,

                 Acceleration=\frac{\text {Force}}{\text {Mass}}

As the force acting on the object is stated as 10 N and the mass of the object is given as 10 kg, then the acceleration will be

                  Acceleration =\frac{10 \mathrm{N}}{10 \mathrm{kg}}=1 \mathrm{m} / \mathrm{s}^{2}

So, the acceleration exerted by the object of mass 10 kg is \mathbf{1} m / \boldsymbol{s}^{2}

4 0
3 years ago
A man takes 20 seconds to climb 5m up a ladder. He weighs 720N. Calculate the power he must deliver to do this.
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Answer:

180 W

Explanation:

The work done by the man against gravity is equal to its gain in gravitational potential energy:

W=mg\Delta h

where

(mg) = 720 N is the weight of the man

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Substituting,

W=(720)(5)=3600 J

The power he must deliver is given by

P=\frac{W}{t}

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W = 3600 J

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Substituting,

P=\frac{3600}{20}=180 W

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