the area of a rectangle is 54x^9y^8 square yards if the length of the rectangle is 6x^3y^4 yards what expression represents the
width of the rectangle in yards
2 answers:
We are given rectangle
![Area=54x^9y^8](https://tex.z-dn.net/?f=%20Area%3D54x%5E9y%5E8%20)
so, we have
![A=54x^9y^8](https://tex.z-dn.net/?f=%20A%3D54x%5E9y%5E8%20)
![length=6x^3y^4](https://tex.z-dn.net/?f=%20length%3D6x%5E3y%5E4%20)
so, we have
![L=6x^3y^4](https://tex.z-dn.net/?f=%20L%3D6x%5E3y%5E4%20)
Let's assume
width of the rectangle in yards as W
we know that
![A=L*W](https://tex.z-dn.net/?f=%20A%3DL%2AW%20)
now, we can plug values
![54x^9y^8=(6x^3y^4)*W](https://tex.z-dn.net/?f=%2054x%5E9y%5E8%3D%286x%5E3y%5E4%29%2AW%20)
now, we can solve for W
![W=\frac{54x^9y^8}{6x^3y^4}](https://tex.z-dn.net/?f=%20W%3D%5Cfrac%7B54x%5E9y%5E8%7D%7B6x%5E3y%5E4%7D%20)
![W=9x^6y^4](https://tex.z-dn.net/?f=%20W%3D9x%5E6y%5E4%20)
so, width of rectangle is
............Answer
I think your answer will be 48x^6y^4
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