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s2008m [1.1K]
3 years ago
9

the area of a rectangle is 54x^9y^8 square yards if the length of the rectangle is 6x^3y^4 yards what expression represents the

width of the rectangle in yards
Mathematics
2 answers:
user100 [1]3 years ago
8 0

We are given rectangle

Area=54x^9y^8

so, we have

A=54x^9y^8

length=6x^3y^4

so, we have

L=6x^3y^4

Let's assume

width of the rectangle in yards as W

we know that

A=L*W

now, we can plug values

54x^9y^8=(6x^3y^4)*W

now, we can solve for W

W=\frac{54x^9y^8}{6x^3y^4}

W=9x^6y^4

so, width of rectangle is 9x^6y^4............Answer


valentinak56 [21]3 years ago
6 0
I think your answer will be 48x^6y^4
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Answer:

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Step-by-step explanation:

Solutions for the given equations are:

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1.(x+6)(x−6)=0

(x+6)=0,(x−6)=0

x=−6,x=6

2.(x+6)(x+6)=0

(x+6)=0,(x+6)=0

x=−6,x=−6

3.(x−6)(x−6)=0

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x=6,x=6

4.(2x+12)(2x−12)=0

(2x+12)=0,(2x−12)=0

x=−6,x=6

5.(2x−12)(x−12)=0

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Step-by-step explanation:

there you go :)

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