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labwork [276]
3 years ago
7

If m CDE=(3x+10)° m CDF=(x+25)°, and m EDF= 65°. Find m CDF​

Mathematics
1 answer:
aleksley [76]3 years ago
5 0

<em>m</em>∠CDF + <em>m</em><em>∠</em><em>EDF</em><em> </em><em>=</em><em> </em><em>∠</em><em>CDE</em>

<em>x + 25° + 65° = 3x + 10</em>

<em>x + 90° = 3x + 10</em>

<em>90° = 3x + 10 - x</em>

<em>90° = 2x + 10</em>

<em>2x + 10 = 90</em>

<em>2x = 90 - 10</em>

<em>2x = 80</em>

<em>x =  \frac{80}{2}</em>

x = 40°

<em>m</em><em>∠</em>CDE

= 3 × 40 + 10

= 120 + 10

= 130°

<h3>Then , <em>m</em>∠CDF =</h3>

x + 25 \\  = 40 + 25 \\  = 65°

<h2>•°• <em>m</em><em>∠</em>CDF = 65°</h2>

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