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alekssr [168]
3 years ago
5

There is a bag filled with marbles: 5 red, 8 blue, 4 yellow, and 3 green.

Mathematics
1 answer:
likoan [24]3 years ago
7 0

Answer:

Step-by-step explanation:

total marbles=5+8+4+3=20

when he is drawing without replacing means red marble is drawn from 20 marbles.

Blue marble is drawn from 19 marbles.

when he is drawing with replacing means he draws one red marble from 20 marbles.Then he replaces it and draws blue marble from 20 marbles also.

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The sum of 1/6,2/3, and 1/4 is
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¹³/₁₂

<h3>Further explanation</h3>

<u>Given:</u>

\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = ? \ }

  • A fraction represents part of a whole.
  • A fraction consists of a numerator and a denominator. i.e., \boxed{ \ \frac{numerator}{denominator} \ }.
  • The numerator = the number of equal parts of a whole.
  • The denominator = the total number of parts that make up said whole.

From the problems above, the denominator or the bottom numbers are still different. We use the Least Common Multiple (or LCM) to equalize the denominator.

  • Multiples of 3: \boxed{ \ \{3, 6, 9, 12, 15, ... \} \ }
  • Multiples of 4: \boxed{ \ \{4, 8, 12, 16, ... \} \ }
  • Multiples of 6: \boxed{ \ \{6, 12, 18, ... \} \ }

Hence, the LCM for 3, 4, and 6 is 12.

We change the denominator for each fraction to 12.

\boxed{ \ \frac{1}{6} \rightarrow \frac{multiply \ by \ 2}{multiply \ by \ 2} \rightarrow \frac{2}{12} \ }

\boxed{ \ \frac{2}{3} \rightarrow \frac{multiply \ by \ 4}{multiply \ by \ 4} \rightarrow \frac{8}{12} \ }

\boxed{ \ \frac{1}{4} \rightarrow \frac{multiply \ by \ 3}{multiply \ by \ 3} \rightarrow \frac{3}{12} \ }

Then we continue adding fractions.

\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = \frac{2}{12} + \frac{8}{12} + \frac{3}{12} \ }

\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = \boxed{ \ \frac{13}{12} \ } \ }

Thus, the result is \boxed{ \ \frac{13}{12} \ or \ 1\frac{1}{12}\ }

<h3>Learn more</h3>
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Keywords: the sum of ¹/₆, ²/₃, and ¹/₄, fraction, adding, numerator, denominator, still different, LCM

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Step-by-step explanation:

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