Question

Which are the factors of x^2-4x-5

Answer 1

$x^2-4x-5 =\\\\x^2+x-5x-5=\\\\x(x+1)-5(x+1)=\\\\(x-5)(x+1)$

Answer 2

Easy. Given expression in current equation.

$\mathbf{x^2 - 4x - 5}$

First break those following expressions in the current equation into grouped form, as to, relate the value as completely equal and not altering the actual expression. So;

$\mathbf{(x^2 + x) + (- 5x - 5)}$

Factor out the variable of 'x' from the expression of $\mathbf{x^2 + x}$. We are getting by factoring 'x'; $\mathbf{x (x + 1)}$.

Factor out the numbered negative value of '5' from the expression of $\mathbf{- 5x - 5}$. We are getting by factoring '5'; $\mathbf{- 5 (x + 1)}$.

$\mathbf{\therefore \quad x (x + 1) - 5 (x + 1)}$

Factor out the expression as a common term on both side, to obtain the final answer, that is, $\mathbf{(x + 1)}$

$\boxed{\mathbf{\underline{(x + 1)(x - 5)}}}$

Hope it helps.