I assume you mean x squared in the first equation
Because both are equal to y, they are equal to each other so x + 5 = x^2 +3
If we then move everything over to one side, we get x^2 - x - 2 = 0
Then factorise it to (x-2)(x+1) = 0
And solve both parts separately
x + 1 = 0
x = -1
x-2 = 0
x = 2
Sub both values into the simplest equation in this case y=x+5
to get y = 4 and y = 7
Y=1\2x.
hopes this helps you
Answer:
log 2 + 3 logx
Step-by-step explanation:
log 2x^3
log2+logx^3
log^2+3logx
9514 1404 393
Answer:
5 miles
Step-by-step explanation:
Time/speed/distance problems can be worked a number of ways. Here, we want to know the distance walked. We know the total time and the total distance and the two different speeds. So, we can use a variable to represent the value we want to know: w = distance walked (in miles).
The total time is 9:00 -6:50 = 2:10 = 2 1/6 hours = 13/6 hours.
The total time is the sum of times for the two parts of the trip: walking and riding.
walking time = walking distance/walking speed
= w/3
riding time = riding distance/riding speed
= (20-w)/30
The total time is that given above:
w/3 +(20-w)/30 = 13/6
10w +(20 -w) = 65 . . . . . . . . multiply by 30
9w = 45 . . . . . . . . . . . . subtract 20, collect terms
w = 5 . . . . . . . . . . . divide by 9
The girl walked 5 miles.
Revenue = Sales Volume (x) times Price. Price depends on volume sold: the more you are willing to sell per week, the lower your average price will have to be to get them all sold.
<span>eg, if there are a fixed number of buyers with a variety of incomes, then you might be able to sell the first 10 per month for £30 each through the up-market High Street jeweller. If you want to sell an extra 10 per month you might have to reduce the price to £15 and sell them through Asda/WalMart. And to move another 10 per month you may have to sell them from a street stall at £5 each! </span>
