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Goryan [66]
3 years ago
7

Consider the following two expressions, the only difference being the presence or absence of parentheses. expression 1:expressio

n 2:3x2(3x)2 Calculate the difference between the two expressions when x = 3; that is, evaluate both expressions then subtract one value from the other.

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

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16. For quadrilateral ABCD, determine the most precise name for it. A(2,3), B (12,3), C(8,6) and D(5,6). Show your work and expl
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The correct answer is a Trapezoid.
First, I drew and labeled the points on a graph. When these points are connected, you can see that the space between DA and CB is not equal, meaning that the trapezoid is not isosceles.
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What are the roots of the polynomial equation XP-7x= 6x-12? Use a graphing calculator and a system of equations.
Julli [10]

Answer: option B

Step-by-step explanation:

-4, 1, 3

6 0
3 years ago
What is the simplified expression of 14 – 8 + 4 × 11 ÷ 22 + 6 – 11?
dimulka [17.4K]

Answer:

your answer will be 3

Step-by-step explanation:

5 0
3 years ago
- slope = 2/7 ; y-intercept = 0​
Yuri [45]

Answer:

y=2/7x

Step-by-step explanation:

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4 0
3 years ago
Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following p
aev [14]

Answer:

P(X < 3) = 0.7443

Step-by-step explanation:

We are given that the random variable X has a binomial distribution with the given probability of obtaining a success. Also, given n = 6, p = 0.3.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 6

            r = number of success = less than 3

           p = probability of success which in our question is 0.3.

LET X = a random variable

So, it means X ~ Binom(n=6, p=0.3)

Now, Probability that X is less than 3 = P(X < 3)

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

             = \binom{6}{0}0.3^{0} (1-0.3)^{6-0}+ \binom{6}{1}0.3^{1} (1-0.3)^{6-1}+ \binom{6}{2}0.3^{2} (1-0.3)^{6-2}

             = 1 \times 1 \times 0.7^{6}  +6 \times 0.3^{1}  \times 0.7^{5}  +15 \times 0.3^{2}  \times 0.7^{4}

             = 0.11765 + 0.30253 + 0.32414 = 0.7443

Therefore, P(X < 3) = 0.7443.

5 0
3 years ago
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