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Softa [21]
3 years ago
8

Kabir wants to know the volume of a solid right pyramid with a square base. He uses a ruler to measure the length of the base as

8 inches. He then measures the slant height to be 5 inches.
Mathematics
2 answers:
scoray [572]3 years ago
8 0
The volume of a pyramid is one-third of the product of its altitude and area of the base. 

Area of the base = (8 in)² = 64 in²

Altitude:
    The altitude is the length of the right triangle formed from the base and the slant height as the hypotenuse.
                                    (5 in)² = h² + (4 in)²
                                            h = 3 in

Volume:
                                   V = Ah/3
                                   V = (64 in²)(9 in) / 3 = 192 in³

The volume of the solid right pyramid is equal to <em>192 in³</em>. 
nadezda [96]3 years ago
7 0
The hypotenuse of the right triangle used to determine the height is
5 inches

The leg of the right triangle that lies on the same plane as the base is
4 inches

The height of the pyramid is
3 inches

The volume of the solid pyramid is
64 cubic inches
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1. S.A of a cone = 565.56 cm².

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Step-by-step explanation:

Given the following data;

1. Radius, r = 15cm

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Surface area of a cone = πrl

Substituting into the formula, we have;

S.A of a cone = 3.142 * 15 * 12

S.A of a cone = 3.142 * 180

S.A of a cone = 565.56 cm²

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Slant height, l = 11cm

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S.A of a cone = 3.142 * 8 * 11

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Surface area of a sphere = 4πr²

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S.A of a sphere = 4 * 3.142 * 9

S.A of a sphere = 36 * 3.142

S.A of a sphere = 113.112 cm²

4 0
3 years ago
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