Answer:
Find out the how much chlorine is in the pool .
To prove
As given
The amount of chlorine in a swimming pool varies directly with the volume of water.
The pool has 2.5 milligrams of chlorine per liter of water.
i.e
2.5 milligrams of chorine = 1 litre of water
There are 8000 gallons of water in the swimming pool.
As 1 gallons = 3.78541 litre (Approx)
Now convert 8000 gallons of water in litres.
8000 gallons = 8000 × 3.78541 litre
= 30283.28 litres
Now calculate chlorine in the pool for 30283.28 litres of waters.
As
2.5 milligrams of chlorine = 1 litre of water
2.5 × 30283.28 milligrams of chlorine = 30283.28 litre of water
75708.2 milligrams of chlorine for 30283.28 litre of water .
The supplement of < 72 has the same measure as < (4x + 8). Therefore, < (4x + 8) must equal 108°. We can establish the following equality statement to solve for x:
< (4x + 8) + < 72° = 180°
Combine like terms:
4x + 80 = 180°
Subtract 80 from both sides:
4x + 80° - 80° = 180° - 80°
4x = 100
Divide both sides by 4 to solve for x:
4x/4 = 100/4
x = 25
To verify whether the value of x is correct, substitute its value into the equality statement:
< (4x + 8)° + < 72° = 180°
< [4(25) + 8]° + < 72° = 180°
< (100 + 8)° + < 72° = 180°
< 108° + < 72° = 180°
180° = 180° (True statement. Therefore, the correct answer is x = 25).
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Answer: The area of the Polygon D is 36 times larger than the area of the Polygon C.
Step-by-step explanation:
<h3>
The complete exercise is: "Polygon D is a scaled copy of Polygon C using a scale factor of 6. How many times larger is the area of Polygon D than the area Polygon C"?</h3>
In order to solve this problem it is important to analize the information provided in the exercise.
You know that the Polygon D was obtained by multiplying the lengths of the Polygon C by the scale factor of 6.
Then, you can identify that the Length scale factor used is:
Now you have to find the Area scale factor.
Knowing that the Length scale factos is 6, you can say that the Area scale factor is:
Finally, evaluating, you get that this is:
Therefore, knowing the Area scale factor, you can determine that the area of the Polygon D is 36 times larger than the area of the Polygon C.
Answer:
11.2
Step-by-step explanation:
divide 160 by 14.3
Using the given information, we can say the following:
Width (W) = x
Length (L) = (2x - 4)
Area of Rectangle = L × W
Using this, we can formulate an equation for rectangle in question:
x(2x - 4) = 30
Expand and move everything to one side:
2x² - 4x - 30 = 0
Simplify by dividing everything on both sides by 2:
x² - 2x - 15 = 0
Factorise:
(x + 5)(x - 3) = 0
Set each factor equal to 0 and solve for x:
x + 5 = 0
x = -5 (a dimension cannot be negative so this is not the solution we want)
x - 3 = 0
x = 3 (this is the solution)
x = W = 3"
L = 2x - 4
L = 2(3) - 4
L = 2"
So, the length the rectangle is 2" and the width is 3"
