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Sholpan [36]
3 years ago
5

20 POINTS!!! NEED IT FAST. A vehicle travels on a highway at a rate of 65 mi/h. How long does it take the vehicle to travel 25 m

i.

Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0
Depending on Speed and Traffic and Tolls on The Highway It should take 3 minutes on a slow highway and 6 on a fast Highway
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(1-sinx+cosx)^2 = 2(1+sinx)(1+cosx)​
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If you're trying to establish an identity, the given equation is not an identity. The proper identity would be as follows:

(1 - sin(<em>x</em>) + cos(<em>x</em>))² = (1 - sin(<em>x</em>))² + 2 (1 - sin(<em>x</em>)) cos(<em>x</em>) + cos²(<em>x</em>)

… = (1 - 2 sin(<em>x</em>) + sin²(<em>x</em>)) + 2 (1 - sin(<em>x</em>)) cos(<em>x</em>) + cos²(<em>x</em>)

… = 2 - 2 sin(<em>x</em>) + 2 (1 - sin(<em>x</em>)) cos(<em>x</em>)

… = 2 - 2 sin(<em>x</em>) + 2 cos(<em>x</em>) - 2 sin(<em>x</em>) cos(<em>x</em>)

… = 2 (1 - sin(<em>x</em>) + cos(<em>x</em>) - sin(<em>x</em>) cos(<em>x</em>))

… = 2 (1 - sin(<em>x</em>) + cos(<em>x</em>) (1 - sin(<em>x</em>)))

… = 2 (1 - sin(<em>x</em>)) (1 + cos(<em>x</em>))

But if you're trying to solve an equation:

(1 - sin(<em>x</em>) + cos(<em>x</em>))² = 2 (1 + sin(<em>x</em>)) (1 + cos(<em>x</em>))

2 (1 - sin(<em>x</em>)) (1 + cos(<em>x</em>)) = 2 (1 + sin(<em>x</em>)) (1 + cos(<em>x</em>))

(1 - sin(<em>x</em>)) (1 + cos(<em>x</em>)) - (1 + sin(<em>x</em>)) (1 + cos(<em>x</em>)) = 0

(1 + cos(<em>x</em>)) (1 - sin(<em>x</em>) - 1 - sin(<em>x</em>)) = 0

-2 sin(<em>x</em>) (1 + cos(<em>x</em>)) = 0

sin(<em>x</em>) = 0   <u>or</u>   1 + cos(<em>x</em>) = 0

sin(<em>x</em>) = 0   <u>or</u>   cos(<em>x</em>) = -1

[<em>x</em> = arcsin(0) + 2<em>nπ</em>   <u>or</u>   <em>x</em> = arcsin(0) + <em>π</em> + 2<em>nπ</em>]   <u>or</u>

… [<em>x</em> = arccos(-1) + 2<em>nπ</em>]

We have arcsin(0) = 0 and arccos(-1) = <em>π</em>, so the solution set reduces to

<em>x</em> = 2<em>nπ</em>   <u>or</u>   <em>x</em> = (2<em>n</em> + 1)<em>π</em>

(where <em>n</em> is any integer)

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Answer:

Yes; LA (D)

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Also, angle PCT and angle LFA are congruent base on the diagram.  This makes up the "A" part of "LA"

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-2x^2 - 5  is same shape as -2x^2 except that the whole graph is translated verticall downwards 5 units
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