Ask question

Ask question

All categories

2 years ago

15

What is x? 2x = square root of three divided by six

2 answers:

Delvig [45]2 years ago

5 0

Answer:x = (39/2)

Step-by-step explanation:Radical Equation entered : √2x-3 = 6Step by step solution :STEP 1:Isolate the square root on the left hand side Radical already isolated √2x-3 = 6STEP 2:Eliminate the radical on the left hand side Raise both sides to the second power (√2x-3)2 = (6)2 After squaring 2x-3 = 36STEP 3:Solve the linear equation Rearranged equation 2x -39 = 0 Add 39 to both sides 2x = 39 Divide both sides by 2 A possible solution is : x = (39/2)STEP 4:Check that the solution is correct Original equation √2x-3 = 6 Plug in (39/2) for x √2•(39/2)-3 = 6 Simplify √36 = 6 Solution checks !! Solution is: x = (39/2)

Alika [10]2 years ago

5 0

x is 6

Step-by-step explanation:

hope it helps you on what ur doing

You might be interested in

Please determine if the relationship is linear, exponential, or quadratic. justify your answer.

r-ruslan [8.4K]

Answer:

This function is a quadratic.

Explanation:

If you sketch a graph, you will see the points form a U, representing a quadratic function.

3 0

3 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

3 years ago

Willie Workout joined a health club. There was a $50 registration fee, and a $25 monthly fee. If Willie visits the club 3 times

beks73 [17]

25 a month x 12 months= 300
300+50= 350

56 weeks x 3 times a week= 168
350/168= 2.08 each visit

6 0

3 years ago

Read 2 more answers

Pls answer correctly I’ll give you brainliest

Montano1993 [528]

The answer is 0, as there is no slope going up or down.

6 0

3 years ago

27,658÷6<br><br> what's the quotient and remainder?

Len [333]

The quotient refers to an answer that has been divided.
27658/6 = a quotient of 4 with a remainder of (2/3) (two-thirds)

6 0

3 years ago