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tiny-mole [99]
3 years ago
13

What percent of 126 is 22?

Mathematics
2 answers:
zalisa [80]3 years ago
5 0
It is 17%, hope this helps
liberstina [14]3 years ago
5 0
The answer is 17%  your welcome      


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A rectangular room is 4 yards long and 5 yards wide . Lucas is covering the floor with tiles that are 1 square foot . How many t
12345 [234]

Answer:

I think like 21

Step-by-step explanation:

i think it correct but if it not it okay but alaest I try my best on it

4 0
3 years ago
What is the value of x in the figure?<br><br> Enter your answer in the box.
andreyandreev [35.5K]

Answer:

x=29

Step-by-step explanation:

x+61=90

61-61

90-61

x=29

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3 years ago
Read 2 more answers
3 gallons But in pints
MakcuM [25]

Answer: 24 pints

Step-by-step explanation:

multiply the volume value by 8

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8 0
3 years ago
Please help me to answer these questions!! Thank you in advance.
oksano4ka [1.4K]
1. 
5u - 2u = 3u (diff. between longest and shortest)
3u = 87cm
1u = 87cm ÷ 3 = 29cm
5u + 4u + 2u=11u
11u = 11 x 29cm = 319cm

Ans: 319cm

2.
9u = 1350
1u = 1350 ÷ 9 = 150
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Ans: 1650


8 0
3 years ago
For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean
ki77a [65]

Answer:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu=?,\sigma=?)  

We are interested on this probability

P(X>X+3\mu)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

And we can find the following probablity:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a/2.0

3 0
3 years ago
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