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Sever21 [200]
3 years ago
12

Find the domain of the function expressed by the formula:

Mathematics
1 answer:
Simora [160]3 years ago
7 0

Answer:

a. Domain - x= all real numbers

b. Domain - x= all real numbers except 0

c. Domain - x= all real numbers

d. Domain - x= All real numbers

Step-by-step explanation:

The domain of a function is all the possible x values. It is easy to solve for domain by graphing the function.

a graph - blue

b graph - red

c graph - green

d graph - purple

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Alla [95]

Answer:

1=1 times 2/2 1 + 2=2 times 3/2 1 +2+3=3 times 4/2 1+2+3+4=4 times 5/2 1+2+3+4+5=5 times 6/2

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3 years ago
Find the cosine and sine of 210. Round your answers to the nearest hundredth if necessary
Assoli18 [71]
The cosine is -0.88
This is rounded from <span>-0.88387747318

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3 years ago
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explain why an circle would have an infinite number of lines of reflection that would carry the circle into itself?
Irina-Kira [14]
Circles will never have a side but they only have 1 line that can be counted as a side.
7 0
4 years ago
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Which polynomial can be simplified to a difference of squares
Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

First=10a^{2}

Second=16a^{2}

Third=25a^{2}

Fourth=24a^{2}

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

7 0
3 years ago
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boyakko [2]
So, to make a mixed number into an improper fraction, you have to multiply the whole number by the denominator and then add the numerator o that number.
2 and 7/10:
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I hope this helps!
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