The amount of meat on a Subbies foot-long sub follows a Normal distribution, with a mean of 8 ounces and a standard deviation of
0.6 ounce. A random sample of 25 subs is selected every day and measured. What is the probability that the mean weight will exceed 8.2 ounces?
1 answer:
Answer:
95.15%
Step-by-step explanation:
We have that the mean (m) is equal to 8, the standard deviation (sd) 0.6 and the sample size (n) = 25
They ask us for P (x <8.2)
For this, the first thing is to calculate z, which is given by the following equation:
z = (x - m) / (sd / (n ^ 1/2))
We have all these values, replacing we have:
z = (8.2 - 8) / (0.6 / (25 ^ 1/2))
z = 1.66
With the normal distribution table (attached), we have that at that value, the probability is:
P (z <1.66) = 0.9515
It means that the probability that it exceeds 8.2 ounces is 95.15%
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Answer:
The least common denominator of the fractions is 24
Step-by-step explanation:
we know that
The <u>least common denominator</u> (LCD) is the smallest number that can be a common denominator for a set of fractions
so
we have
7/8
Multiples of 8 -------> 8,16,24,32,...
5/6
Multiples of 6 -------> 6,12,18,24,...
24 is a common multiple of 6 and 8. It is their lowest common multiple
<em>Alternative Method</em>
we have
The least common multiple are those common and non-common numbers with the greatest exponent
so