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Svetradugi [14.3K]
3 years ago
5

Find the following difference by changing into sums with multiplication by a negative number.

Mathematics
1 answer:
Ahat [919]3 years ago
4 0
2(3x+7) it is the correct answer
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$1400 deposit that earns 10% annual interest compounded semiannually
____ [38]

Answer:Does this helpf(t) = 1400(1 + (0.1)/2))2t

Step-by-step explanation:

3 0
3 years ago
Question 131 ptsIt takes a team of 8 workers 2 hours and 15 minutes to clean 12 apartments. Howmany apartments can the tearsclea
Amanda [17]
48\:apartments\:in\:9\:hours

1) In this problem, the first thing to do is to enlist the categories:

workers time to clean # apartments

8 2h15 12

8 9 x

2) Note that the number of cleaners is the same. So, we can pick the ratios that fall under the category <em>time </em>and <em>#apartments</em>

<em />

We need to convert that 2h 15 into decimal form before setting the ratios:

2h15\:2+\frac{15}{60}=2.25

3) Now, we can set the ratios and solve for x:

\begin{gathered} \frac{2.25}{9}=\frac{12}{x} \\ 2.25x=12\cdot9 \\ \frac{2.25x}{2.25}=\frac{108}{2.25} \\ x=48 \end{gathered}

Thus, the answer is 48

5 0
1 year ago
A+B-C=3pi then find sinA+sinB-sinC
steposvetlana [31]
The answer:
the full question is as follow:

if A+B-C=3pi, then find sinA+sinB-sinC

first, the main formula of sine and cosine are:
sinC = 2sin(C/2)cos(C/2)
sinA +sinB = 2sin[(A+B)/2]cos[(A-B)/2]

therefore: 
 sinA+sinB-sinC = 2sin[(A+B)/2]cos[(A-B)/2] - 2sin(C/2)cos(C/2)

sin[(A+B)/2] = cos(C/2)
2sin(C/2)cos(C/2) = cos[(A+B)/2
and 
A+B-C=3 pi implies A+B =3 pi + C, so 
cos[(A+B)/2] = cos [3 pi/2  + C/2]
and  with the equivalence cos (3Pi/2  + X) = sinX

sinA+sinB-sinC =  cos(C/2)+ sin(C/2) 
7 0
3 years ago
HELLO ME I NEED HELP SO BAD
irina [24]

Answer:

up 3 units

Step-by-step explanation:

y = f(x) + C   C > 0 moves it up

We are moving the graph up 3 units

4 0
3 years ago
Which expression is equivalent to √4j^4/9k^8?
solmaris [256]
\frac{ 2j^{2} }{ 3^{4} }
SQRT each individual bit: 4 andj^{4} and 9 and k^{8}
6 0
4 years ago
Read 2 more answers
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