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Phantasy [73]
3 years ago
12

What is the value of (-3+3i)+(-2+3i)?

Mathematics
2 answers:
I am Lyosha [343]3 years ago
4 0

Answer:

The value is  of given expression is -5+6i.

Step-by-step explanation:

The given expression is

(-3+3i)+(-2+3i)

It can be written as

-3+3i-2+3i

Now combine like terms.

(-3-2)+(3i+3i)

(-3-2)+(3+3)i

Simplify each parenthesis.

(-5)+(6i)

-5+6i

Therefore the value is  of given expression is -5+6i.

Yakvenalex [24]3 years ago
3 0
-3+(-2)= -5
-5+ 3i + 3i =
-5 + 6i
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(100+ POINTS)
horsena [70]

Answer:

1) 102.7 meters

2) 11

Step-by-step explanation:

1) -4.9x² + 75x = -4.9x² + 50x + 38

25x = 38

x = 1.52 s

Height = -4.9(1.52)² + 75(1.52) = 102.67904 m = 102.7 m

2) f(x) = x² + 3x - 2

f(2) = 2² + 3(2) - 2 = 8

f(6) = 6² + 3(6) - 2 = 52

Average rate of change:

(52-8)/(6-2) = 11

5 0
3 years ago
Read 2 more answers
Which of the equations below could be the equation of this parabola?
Aleonysh [2.5K]

Answer:

C. x=-3y^2

Step-by-step explanation:

The group of parabola opens left so, x=ay^2

parabola opens left so a in negative x=-3y^2

Hope it helps....

8 0
3 years ago
If 3/8 of my money is $3840.00. How much did I have at first? *
NNADVOKAT [17]

Answer:

E $10240.00

Step-by-step explanation:

The total amount of money is x.

3/8 × x = 3840

Multiply both sides by the reciprocal of 3/8 which is 8/3.

x = 3840 × 8/3

x = 10240

Answer: E $10240.00

7 0
2 years ago
Read 2 more answers
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
What is the product of (-6)(-7)(-1)?<br> оооо
Yanka [14]

Answer:

-42

Explanation:

(-6)(-7)(-1)

do (-6)(-7)

-negative sign and -negative sign= +positive sign

(-6)(-7)=42

(42)(-1)

+positive sign and -negative sign=-negative sign

answer:

-42

3 0
3 years ago
Read 2 more answers
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