To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
10
Step-by-step explanation:
p² +3q
= 2² +3*2
=4 + 6
=10
Answer:
A) JK and AB =
![[tex] \boxed{( \theta) = \f{12}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%5Cf%7B12%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, =》 
=》 
[/tex]
B) AABC
![[tex] \boxed{( \theta) = {1}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%7B1%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, 
C) AABM:
![[tex] e \fbox{: }](https://tex.z-dn.net/?f=%5Btex%5D%20e%20%5Cfbox%7B%3A%20%7D)
The value of k for which 
is 
ans[/tex]
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The volume is 378 ft³. Hope this helps! Good luck.
<span>4(13.5) / 3(10) = 1.8
Example
1. 9(499) = 4491 = (200 + 299)9
For the basic properties examples are:
Addition, you can have 6 + 107 = 113 </span>
Commutative Property by moving: 107 + 6 = 113
Associative Property by grouping: (3 + 3) + (100 + 7 ) = 113
Distributive Property by allotting: 2 (3) + 107 = 113
Multiplication, you can have 6 x 107 = 642
Commutative Property by moving: 107 x 6 = 642
Associative Property by grouping: (3 + 3) x (100 + 7 ) = 642
<span>Distributive Property by allotting: 2(3) x 107 = 642<span>
</span></span>
