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Alina [70]
3 years ago
15

If there 3 cats and 3 dogs how mush would be together

Mathematics
2 answers:
vovikov84 [41]3 years ago
8 0

Answer:

<em>There is 1 cat for each dog so the ratio would be 1:1 together.</em>

Step-by-step explanation:

<em> This means there are twice as many cats as dogs, or half as ... The ratio of 6:3 reduces to the ratio of 1:1</em>

WARRIOR [948]3 years ago
5 0

Answer:

6

Step-by-step explanation:

3+3 = 6

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Plz someone help ASAP! thanks​
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Answer:

B

Step-by-step explanation:

Because <u>at least </u>means not less than 50 or equal to 50

Since he wrote 18 pages then you have to add.

8 0
2 years ago
Anyone have the answer to number 6
stiv31 [10]
It is between c 12 and d 13
12 cartons will be 15 
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6 0
3 years ago
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250 squared to the nearest tenth
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4 0
3 years ago
3. Two balls are drawn in succession without replacement from an urn containing 4 red balls and 3 blue balls. Find the probabili
choli [55]

Answer:

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

Step-by-step explanation:

Given that :

Number of red balls = 4

Number of Blue balls = 3

Total number of balls = (4 + 3) = 7

Picking without replacement :

Number of picks = 2

1st pick is red :

Probability = (required outcome / Total possible outcomes)

USing combination formula :

nCr = n! / (n-r)! r!

Total possible outcome :

7C2 = 7! / 5!2! = 7*6 / 2 = 42 / 2 = 21

X = number of red

For red = 0;

P(x =0) = required outcome / Total possible outcomes

P(x = 0)

Required outcome : [4C0 * 3C2)]

P(x = 0) = [(4C0 * 3C2)] / 21 = (1*3)/21 = 3/21 = 1/7

P(x = 1)

Required outcome : [4C1 * 3C1)]

P(x = 1) = [(4C1 * 3C1)] / 21 = (4*3)/21 = 12/21 = 4/7

P(x = 2)

Required outcome : [4C2 * 3C0)]

P(x = 2) = [(4C2 * 3C0)] / 21 = (6*1)/21 = 6/21 = 2/7

Hence ;

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

8 0
3 years ago
True or false?<br> All quadrilaterals are also rhombuses.
Molodets [167]

Answer:

It's false

All quadrilaterals are also rhombus, <u>False</u>

4 0
3 years ago
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