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olchik [2.2K]
3 years ago
11

Is LMN = OPQ? If so name the congruence postulate that applies

Mathematics
1 answer:
devlian [24]3 years ago
5 0
<h2>Explanation:</h2><h2></h2>

The complete question is shown below. As you can see, we know that:

\triangle LMN \cong \triangle OPQ

Shapes are congruent if you can turn one into the other by moving, rotating or flipping. If any two triangles have matching side lengths, they're not necessarily congruent. The same happens if they have two matching side lengths, but If triangles have three matching side lengths, then they must be congruent. This is is known as the Side-Side-Side Postulate (SSS). Since in this problem corresponding sides measures the same, therefore we can say that the postulate that applies is:

B. Congruent - SSS

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The museum of fine arts decides to expand its collection of European, Latin American and African art. After reviewing their curr
skad [1K]

Answer:

Step-by-step explanation:

Latin American Art: x

African American Art: x+18

European Art: x-15

x+x+18+x-15=78

3x+3=78

3x=75

x=25

Latin American Art: 25

African American Art: 43

European Art: 10

8 0
3 years ago
Read 2 more answers
At Stephanie's new job, she spent $6.50, $8, $7.25, $13.50, and $9.75 on lunch the first week. In the second week, Stephanie spe
MaRussiya [10]

Answer:

The mean for the second week is $2 less than the first and in percentage it is 22% less.

Step-by-step explanation:

The mean is given by the sum of all individual values divided by the number of values. For the first week the sum is:

sum1 = 6.5 + 8 + 7.25 + 13.5 + 9.75

sum1 = 45

Since she spent 10 less in the second week the sum is:

sum2 = sum1 - 10 = 45 - 10 = 35

The mean for each week is:

mean1 = sum1/5 = 45/5 = 9

mean2 = sum2/5 = 35/5 = 7

difference = mean1 - mean2 = 9-7 = 2

difference(%) = [2/9]*100 = 0.22*100 = 22%

The mean for the second week is $2 less than the first and in percentage it is 22% less.

6 0
3 years ago
Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
3 years ago
The ratio of the number of boys to the number of girls in a school is 5:7.If there are 600 students in the school,how many girls
nekit [7.7K]
So,

The secret to solving problems with ratios is to find the value of one unit.

5:7 = 12 units total

To find one unit, divide the total number of students by the total number of units.
600/12 = a

Simplify
50/1 = a
50 = a

The value of each unit is 50.

Now, multiply the units by the numbers in the ratio.
50(5) = b
250 = boys

50(7) = x
350 = x

There are 350 girls.
3 0
3 years ago
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Two girls used the same number of beads to make a necklace. Farah used 2/5 of hers and Rani used 1/4 of hers. They had a total o
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Farah=52 rani=33 I think this is right
8 0
3 years ago
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