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olchik [2.2K]
4 years ago
11

Is LMN = OPQ? If so name the congruence postulate that applies

Mathematics
1 answer:
devlian [24]4 years ago
5 0
<h2>Explanation:</h2><h2></h2>

The complete question is shown below. As you can see, we know that:

\triangle LMN \cong \triangle OPQ

Shapes are congruent if you can turn one into the other by moving, rotating or flipping. If any two triangles have matching side lengths, they're not necessarily congruent. The same happens if they have two matching side lengths, but If triangles have three matching side lengths, then they must be congruent. This is is known as the Side-Side-Side Postulate (SSS). Since in this problem corresponding sides measures the same, therefore we can say that the postulate that applies is:

B. Congruent - SSS

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6:7

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Mean: 116

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Which decimal number is equal to 2/3? <br><br><br> 0.6<br><br> 0.66<br><br> 0.6.......<br><br> 0.67
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Solve 4(3x+3)=15x+7-3x+5
Flura [38]

Answer:

Infinite amount of solutions

Step-by-step explanation:

Step 1: Write equation

4(3x + 3) = 15x + 7 - 3x + 5

Step 2: Solve for <em>x</em>

  1. Distribute 4: 12x + 12 = 15x + 7 - 3x + 5
  2. Combine like terms: 12x + 12 = 12x + 12
  3. Subtract 12 on both sides: 12x = 12x
  4. Divide both sides by 12: x = x

Here, we can see that <em>x</em> would be infinite amount of solutions. We can plug in any number <em>x</em> and it would render the equation true.

4 0
3 years ago
1. The mechanics at Lincoln Automotive are reborning a 6 in deep cylinder to fit a new piston. The machine they are using increa
Firdavs [7]

Answer:

0.0239\frac{in^{3}}{min}

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)

This diagram will help us visualize the problem better.

So we start by determining what data we already know:

Height=6in

Diameter=3.8in

Radius = 1.9 in (because the radius is half the length of the diameter)

The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:

r'=\frac{1/1000in}{3min}

which yields:

r'=\frac{1}{3000}\frac{in}{min}

with this information we can start solving the problem.

First, the problem wants us to know how fast the volume is increasing, so in order to find that we need to start with the volume formula for a cylinder, which is:

V=\pi r^{2}h

where V is the volumen, r is the radius, h is the height and π is a mathematical constant equal approximately to 3.1416.

Now, the height of the cylinder will not change at any time during the reborning, so we can directly substitute the provided height, so we get:

V=\pi r^{2}(6)

or

V=6 \pi r^{2}

We can now take the derivative to this formula so we get:

\frac{dV}{dt}=2(6)\pi r \frac{dr}{dt}

Which simplifies to:

\frac{dV}{dt}=12\pi r \frac{dr}{dt}

We can now substitute the data provided by the problem to get:

\frac{dV}{dt}=12\pi (1.9) (\frac{1}{3000})

which yields:

\frac{dV}{dt}=0.0239\frac{in^{3}}{min}

3 0
4 years ago
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