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Bas_tet [7]
3 years ago
9

The point-slope form of the equation of the lin that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standa

rd form of the equation for this line?
Mathematics
1 answer:
Natali5045456 [20]3 years ago
4 0
I got -x+y=11 but I’m probably wrong lol
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Find the determinant of the following matrix. A =<br>-2 6<br>3 5​
Blababa [14]

Answer:

|A| = - 28

Step-by-step explanation:

Given

A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]

Required

Determine the determinant

For a two by two matrix, A such that:

A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]

The determinant |A| is:

|A| = a * d - b * c

So, in

A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]

The determinant is:

|A| = -2 * 5 - 6 * 3

|A| = -10 - 18

|A| = - 28

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