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Ber [7]
3 years ago
12

The mean age of a student book club is 14.2 years. A 27-year-old teacher is invited to join the club. How does the teacher’s age

affect the mean?
A. The new mean age will be 20.6 years.

B. The new mean age will be greater than 14.2 years.

C. The new mean age will be less than 14.2 years.

D. The new mean age will still be 14.2 years.
Mathematics
2 answers:
IgorC [24]3 years ago
7 0
I think its b.im not sure though.
MAXImum [283]3 years ago
3 0
The new mean age will be greater than 14.2 years because the teacher is older than the previous mean.
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Mr. Sanchez’s class sold fruit pies for $1.55 each and Mr. Kelly’s class sold bottles of fruit juice for $1.40 each. Together, t
Blababa [14]

Answer:

x + y = 60 and 1.55x + 1.4y = 88.20 and the solution is x = 32 and y = 28.

Mr. Sanchez’s class earned more money by $10.4.

Step-by-step explanation:

Mr. Sanchez’s class sold fruit pies for $1.55 each and Mr. Kelly’s class sold bottles of fruit juice for $1.40 each.

Let the number of sold fruit pies is x and bottles of fruit juice is y.

So, from the given condition we can write

x + y = 60 ........ (1)

⇒ 1.4x + 1.4y = 84 ....... (2) and

1.55x + 1.4y = 88.20 ........ (3)

Now, solving equations (2) and (3) we get (1.55 - 1.4)y = (88.2 - 84)

⇒ y = 28

And from equation (1) we get x = 60 - 28 = 32.

Therefore, Mr. Sanchez’s class earned more money. (Answer)

Now, this class have earned $(32 × 1.55 - 28 × 1.4) = $10.4 more. (Answer)

5 0
3 years ago
Read 2 more answers
Please show your work and explain it.
Maru [420]

Answer:

f(x)=\dfrac{x+2}{2(x-2)}

Step-by-step explanation:

Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

\dfrac{x^2+4x+4}{x^2-6x+8}\div\dfrac{6x+12}{3x-12}\\\\=\dfrac{x^2+4x+4}{x^2-6x+8}\times\dfrac{3x-12}{6x+12}\\\\=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}

Next we factor what we can so we can further simplify the rest of the equation:

=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}\\\\=\dfrac{(x+2)(x+2)(3x-12)}{(x^2-6x+8)(6(x+2))}\\\\

We can now cancel out (x+2)

=\dfrac{(x+2)(3x-12)}{(x^2-6x+8)(6)}

Next we factor out even more:

=\dfrac{(x+2)(3)(x-4)}{(x-2)(x-4)(6)}

We cancel out x-4 and reduce the 3 and 6 into simpler terms:

=\dfrac{(x+2)(1)}{(x-2)(2)}

And we can now simplify it to:

=\dfrac{x+2}{2(x-2)}

6 0
3 years ago
NO LINKS<br> Solve for a:<br> a/0.2-10=20<br><br> -6<br> -4<br> 4<br> 6
lapo4ka [179]

Answer:

6

Step-by-step explanation:

5 0
3 years ago
If F(X)= 6X-4 and F(A)= 26 what is the value of a? Explain
sammy [17]
Easy if you know the formula

all this means is that your x value is a, and when it is, will give you the value 26.

f(a) = 6a - 4 = 26

6a = 30
a = 5
3 0
3 years ago
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HELPPPPP I NEED HELP ON THIS
rjkz [21]

Answer:

$51

Step-by-step explanation:

3 0
3 years ago
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