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GarryVolchara [31]
3 years ago
10

True or False... P^2+2pq+q^2= 1

Mathematics
2 answers:
Anestetic [448]3 years ago
8 0
F stands for false my friend  
nadya68 [22]3 years ago
7 0

Answer:

defiantly a false!!

Step-by-step explanation:

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NikAS [45]

Answer:

x = -6/7

Step-by-step explanation:

5 – 6x = 8x + 17

-5                 - 5           Subtract 5 from both sides

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-8x   - 8x                     Subtract 8x from both sides

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x = -12/14                     Simplify

x = -6/7

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3 years ago
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Step-by-step explanation:

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Answer:

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3 years ago
Use the pythagorean theorem to find the missing side. Round your answer to the nearest tenth
Monica [59]

Answer:

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Step-by-step explanation:

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7-18 use part 1 of the fundamental theorem of calculus to find the derivative of the function.
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\displaystyle h(x)=\int\limits_{1}^{\sqrt{x}}~\cfrac{z^2}{z^4+1}dz~\hspace{10em}\cfrac{dh}{du}\cdot \stackrel{chain~rule}{\cfrac{du}{dx}\implies \cfrac{dh}{dx}} \\\\[-0.35em] ~\dotfill\\\\ u=\sqrt{x}\implies \cfrac{du}{dx}=\cfrac{1}{2\sqrt{x}} \\\\[-0.35em] ~\dotfill

\cfrac{dh}{dx}\implies \displaystyle \cfrac{d}{du}\left[ \int\limits_{1}^{u}~\cfrac{z^2}{z^4+1}dz \right]\cdot \cfrac{1}{2\sqrt{x}}\implies \left[ \cfrac{u^2}{u^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}} \\\\\\ \stackrel{substituting~back}{\left[ \cfrac{(\sqrt{x})^2}{(\sqrt{x})^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}}}\implies \cfrac{x}{x^2+1}\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{\sqrt{x}}{2x^2+2}

7 0
2 years ago
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