( - 14x^3)(y^3) + 4x^5y^6)/(2x^4y^5)
= 4x^5y^6 - 14x^3y^3/2x^4y^5
= 4x^2y^3 - 14/2xy^2
= 2x^2y^3 - 7/xy^2
Answer: 2x^2y^3 - 7/xy^2
Hope that helps!!!!
Answer:
See below for answers and explanations
Step-by-step explanation:
<u>Problem 1:</u>
A standard deck of cards contains 52 cards, consisting of 13 spades. If you select only one randomly, the probability of that occurring would be 13/52 or 1/4. Since there are only 26 red cards in a standard deck, then the probability of selecting a red card would be 26/52 or 1/2. Because the two events are independent of each other, their probabilities are multiplied. Therefore, the probability of selecting a spade, and then replacing it in hopes of drawing a red card is (1/2)(1/4) = 1/8.
<u>Problem 2:</u>
We are selecting a spade and then another spade while NOT replacing the first spade (remember that these events are independent of each other also). This means that the total card count will change by picking up the second card. Therefore, the probability of selecting a spade, followed by another spade, is (13/52)(12/51) = 156/2652 = 1/17.
Answer:
* 5+2k+n
Step-by-step explanation:
Combine all like terms:
7-2 = 5
5k-3k = 2k
n = n
Answer:
You would end up at (9,6)
Answer:6=C 7=C
Step-by-step explanation:
