Answer:
0 (I think)
Step-by-step explanation:
(1,6) (3,-6)
X1 Y1. X2 Y2
-6-6= 0
3-1=2
0/2= 0
Given a polynomial
and a point
, we have that

We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of

Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be

To fix the correct value for a, we impose
:

And so we must impose

So, the function we're looking for is

Answer:
Your answer is y.
Step-by-step explanation:
You start graphing by plotting the 2 and the you go two points up and 5 to the right.