Please help me with this math question!

Mathematics

2 answers:

nlexa [21]4 years ago

8 0

If the temperature drops 35 degrees everyday for 7 days, you would have to add -35 + -35 + -35 +-35 + -35 + -35 + -35, since each day it drops the temperature would be -35, now the answer would be -245.

Hopefully this helped. :)

tester [92]4 years ago

6 0

If over 7 days the temp dropped by 35 degrees it would be 35 divided by 7. (because it say total drop in temp which means after 7 days it was 35 degrees colder). so the answer would be, "the temperature dropped 5 degrees every day"

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2(10.8 k+ 2.9) What's the answer

motikmotik

21.6k + 11.8

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3 0

3 years ago

Write the polynomial in factored form as a product of linear factors f(r)=r^3-9r^2+17r-9

adelina 88 [10]

Answer:

f(r) = (x -1)(x -4+√7)(x -4-√7)

Step-by-step explanation:

The signs of the terms are + - + -. There are 3 changes in sign, so Descartes' rule of signs tells you there are 3 or 1 positive real roots.

The rational roots, if any, will be factors of 9, the constant term. The sum of coefficients is 1 -9 +17 -9 = 0, so you know that r=1 is one solution to f(r) = 0. That means (r -1) is a factor of the function.

Using polynomial long division, synthetic division (2nd attachment), or other means, you can find the remaining quadratic factor to be r^2 -8r +9. The roots of this can be found by various means, including completing the square:

r^2 -8r +9 = (r^2 -8r +16) +9 -16 = (r -4)^2 -7

This is zero when ...

(r -4)^2 = 7

r -4 = ±√7

r = 4±√7

Now, we know the zeros are {1, 4+√7, 4-√7), so we can write the linear factorization as ...

f(r) = (r -1)(r -4 -√7)(r -4 +√7)

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<em>Comment on the graph</em>

I like to find the roots of higher-degree polynomials using a graphing calculator. The red curve is the cubic. Its only rational root is r=1. By dividing the function by the known factor, we have a quadratic. The graphing calculator shows its vertex, so we know immediately what the vertex form of the quadratic factor is. The linear factors are easily found from that, as we show above. (This is the "other means" we used to find the quadratic roots.)