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3 years ago

Write y^2*y^4 without exponents

Mathematics

1 answer:

marin [14]3 years ago

4 0

Y²×y⁴

Multiply.

y⁶

y × y × y × y × y × y

~Hope I helped!~

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4 years ago

How to evaluate -4+3/4 plzzzz!

Pachacha [2.7K]

Answer:

-13/4

Step-by-step explanation:

Look for the LCM of both which is 4. 4÷1 ×-4 which is -16

then 4 divided by 4 which is 1 then × 3 which is 3.

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3 years ago

You have drawn a simple random sample of 36 college students, asking each student how much rent they pay per month. You obtain a

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Answer:

$573-1.690\frac{22}{\sqrt{36}}=566.8033$

$573+1.690\frac{22}{\sqrt{36}}=579.1967$

And the 90% confidence interval would be between [566.80 and 579.20]

Step-by-step explanation:

Information given

$\bar X=573$ represent the sample mean

$\mu$ population mean (variable of interest)

s=22 represent the sample standard deviation

n=36 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=36-1=35$

The Confidence level is 0.90 or 90%, the significance would be $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value for this case would be $t_{\alpha/2}=1.690$

And replacing we got:

$573-1.690\frac{22}{\sqrt{36}}=566.8033$

$573+1.690\frac{22}{\sqrt{36}}=579.1967$

And the 90% confidence interval would be between [566.8033 and 579.1967]

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