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VARVARA [1.3K]
3 years ago
12

Why do you think rates are usually written as unit rates

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0

Answer: A rate is a ratio of two quantities: miles per hour, calories per cookie, dollars per person, ... a unit rate just specifies the units (miles, hours) of the two quantities.

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4x+3y-2(x to the second power +3) x=4 y=6
nalin [4]
The answer to 4x×3y-2 (x to the second power ×3) x=4 y=6
The answer is 35
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The equation d=4 -1/15t represents your distance from home,d, for each minute you walk,t. If you graphed this equation, determin
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we have

d=4 -\frac{1}{15}t

using a graph tool

see the attached figure

For t=0 d=4 -------> the y-intercept

that means that at the time t=0 the house was four units away.

For t=60 min  d=0 -------> x-intercept

that means he was already at home at the time t=60 minutes.

therefore

the graph of this equation represents the walk towards the house

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3 years ago
Choose the correct graph! asap please!
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Answer:

Thats all the gave you??

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How do I do this? please detail steps.
vladimir2022 [97]
Define
{x} =   \left[\begin{array}{ccc}x_{1}\\x_{2}\end{array}\right]

Then
x₁ = cos(t) x₁(0) + sin(t) x₂(0)
x₂ = -sin(t) x₁(0) + cos(t) x₂(0)

Differentiate to obtain
x₁' = -sin(t) x₁(0) + cos(t) x₂(0)
x₂' = -cos(t) x₁(0) - sin(t) x₂(0)

That is,
\dot{x} =   \left[\begin{array}{ccc}-sin(t)&cos(t)\\-cos(t)&-sin(t)\end{array}\right] x(0)

Note that
\left[\begin{array}{ccc}0&1\\-1&09\end{array}\right]   \left[\begin{array}{ccc}cos(t)&sin(t)\\-sin(t)&cos(t)\end{array}\right] =  \left[\begin{array}{ccc}-sin(t)&cos(t)\\-cos(t)&-sin(t)\end{array}\right]

Therefore
x(t) =   \left[\begin{array}{ccc}0&1\\-1&0\end{array}\right] x(t)

7 0
3 years ago
How many metres are there in 200cm
Arturiano [62]
1m=100cm\Rightarrow1cm=0.01m\\\\200cm=200\times0.01m=2m
5 0
3 years ago
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