Answer:
The answer to your question is $1.29
Step-by-step explanation:
Data
Total amount of cupcakes = 50
Total amount of sugar = 3 1/2 cups = 3.5 cups
Cost of 5-pound bag = $3.69
2 cups = 1 pound
Total cost = ?
Process
1.- Calculate the amount of pounds needed
2 cups ------------------ 1 pound
3.5 cups --------------- x
x = (3.5 x 1) / 2
x = 3.5 / 2
x = 1.75 pounds
2.- Calculate the price of 1.75 pounds
5 pounds -------------- $3.69
1.75 pounds ---------- x
x = (1.75 x 3.69)/5
x = 6.46/5
x = $1.29
3.- Conclusion
The cost of sugar to prepare 50 cupcakes is $1.29
The answer is A. 24 yards because to find perimeter, you add up the lengths of all four sides
Taking into account the definition of percentage, the correct option is: 21 percent of her net pay is left for savings.
First of all, the percentage represents a given quantity that establishes relationships between two quantities, using the number 100 as a reference.
That is, the percentage indicates what part of a total represents a quantity.
To obtain the percentage, the division must be made between the portion of the total and the total amount that belongs to the set, whose result is multiplied by 100.
In this case, if Lillie's current monthly net pay and her monthly expenses are $ 387.10, and I assume that the rest of the money is saved by Lillie, then the amount of money saved is $ 490 - $ 387.10 = $ 102.9.
Then:
- portion of the total= amount of money saved= $102.9
- total amount= Lillie's current monthly net pay= $490
So, the percentage is calculated as:
percentage= (102.9÷490) ×100
percentage= 0.21×100
percentage= 21%
The correct option is: 21 percent of her net pay is left for savings.
Learn more about percentage with this examples:
so we have the points of (0,-7),(7,-14),(-3,-19), let's plug those in the y = ax² + bx + c form, since we have three points, we'll plug each one once, thus a system of three variables, and then we'll solve it by substitution.
well, from the 1st equation, we know what "c" is already, so let's just plug that in the 2nd equation and solve for "b".
well, now let's plug that "b" into our 3rd equation and solve for "a".
![\bf -19=9a-3b-7\implies -12=9a-3b\implies -12=9a-3(-1-7a) \\\\\\ -12=9a+3+21a\implies -15=9a+21a\implies -15=30a \\\\\\ -\cfrac{15}{30}=a\implies \blacktriangleright -\cfrac{1}{2}=a \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{and since we know that}}{-1-7a=b}\implies -1-7\left( -\cfrac{1}{2} \right)=b\implies -1+\cfrac{7}{2}=b\implies \blacktriangleright \cfrac{5}{2}=b \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{2}x^2+\cfrac{5}{2}x-7~\hfill](https://tex.z-dn.net/?f=%5Cbf%20-19%3D9a-3b-7%5Cimplies%20-12%3D9a-3b%5Cimplies%20-12%3D9a-3%28-1-7a%29%20%5C%5C%5C%5C%5C%5C%20-12%3D9a%2B3%2B21a%5Cimplies%20-15%3D9a%2B21a%5Cimplies%20-15%3D30a%20%5C%5C%5C%5C%5C%5C%20-%5Ccfrac%7B15%7D%7B30%7D%3Da%5Cimplies%20%5Cblacktriangleright%20-%5Ccfrac%7B1%7D%7B2%7D%3Da%20%5Cblacktriangleleft%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Band%20since%20we%20know%20that%7D%7D%7B-1-7a%3Db%7D%5Cimplies%20-1-7%5Cleft%28%20-%5Ccfrac%7B1%7D%7B2%7D%20%5Cright%29%3Db%5Cimplies%20-1%2B%5Ccfrac%7B7%7D%7B2%7D%3Db%5Cimplies%20%5Cblacktriangleright%20%5Ccfrac%7B5%7D%7B2%7D%3Db%20%5Cblacktriangleleft%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20y%3D-%5Ccfrac%7B1%7D%7B2%7Dx%5E2%2B%5Ccfrac%7B5%7D%7B2%7Dx-7~%5Chfill)
Answer:
Laura has $4.50 in dimes and quarters she has 3 more dimes than quarters How many quarters does she have
She has 3 more dimes than quarters. How many quarters does she have? Laura has 15 dimes and 12 quarters.
Step-by-step explanation:
