Answer: 
<u>Step-by-step explanation:</u>
Pythagorean Theorem is: a² + b² = c² , <em>where "c" is the hypotenuse</em>
<em />
Note: 4² + (8√2)² = hypotenuse² → hypotenuse = 12
Note: 12² + opposite² = 20² → opposite = 16
Note: adjacent² + 5² = 6² → adjacent = √11
Note: adjacent² + 7² = (13√2)² → adjacent = 17
Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
First can you change
2x + y = -12
To have y as the subject
Looks like y = ???
Answer:
r = 10 cm
Step-by-step explanation:
r² = 8² + 6²
r² = 64 + 36 = 100
r = 10 cm
Answer:
SOLUTION: X=5
Step-by-step explanation:
x=5
y=27
vertical input= (0, 1/9)
Hope that helps!
