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3 years ago

Josh will take 10 tests in 5 weeks of school. How many tests will he have taken after 7 weeks?

Mathematics

1 answer:

stira [4]3 years ago

5 0

<h2>10/5=2 test per week</h2><h2>7x2=14</h2><h2>Josh took 14 test in 7 weeks</h2>

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Can you help me with this please???

Alecsey [184]

So let’s say you have (2,8) and (4,12)
Your x values are your first ones. So 2 and 4.
that formula is to find the midpoint so let 2 by x1 and 4 be x2. Add those together you get 6. Then divide by 2. Always by 2. You get 3. That’s the midpoint of those two points. Same thing for the y values.

4 0

3 years ago

Trevor bought 3 shirts that all cost the same amount. He also bought a jacket for $47.15. With the given information in the torn

KengaRu [80]

Answer: See explanation

Step-by-step explanation:

Your question isn't complete but let me help out. The value of each shirt will be gotten by subtracting $47.15 from the total amount paid for the shirt and jacket. Let's say the total amount paid is $90.02

Since the jacket cost $47.15, the cost of the shirts will be:

= $90.02 - $47.15

= $42.87

We would now divide the coat if the three shirts by 3. This will be:

= $42.87 ÷ 3

= $14.29

6 0

3 years ago

PLEASE HELPPP MEEEEEEEEEEEEEEE

Papessa [141]

The answer would be

4d+2.75p=12

7 0

3 years ago

Read 2 more answers

John bought candy for $4.50 per pound.He spent a total of $36.00.How many pounds of candy did he buy?

ExtremeBDS [4]

Answer:

8 pounds. 36/4.5 is 8 so that's the answer

3 0

3 years ago

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.