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denpristay [2]
2 years ago
9

A typical adult human body contains approximately 2.500 L of blood plasma. How many grams of blood plasma are in the typical adu

lt human body? The density of blood plasma is 1.03 g/mL.
Chemistry
1 answer:
kirill115 [55]2 years ago
7 0

Answer:

m=2.575g

Explanation:

Hello,

In this case, since the density is defined as the ratio of the mass and volume:

\rho =\frac{m}{V}

We can compute the mass of blood as follows:

m=\rho *V=1.03g/L*2.500L\\\\m=2.575g

Best regards.

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Which chemical reaction needs more energy to break bonds in the reactants
MA_775_DIABLO [31]

Answer:An endothermic reaction

Explanation: In an endothermic reaction, it takes more energy to break the bonds of the reactants than is released when the bonds in the products are formed. In an endothermic reaction, the temperature goes down.

6 0
3 years ago
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Which of the following depicts a molecule of DNA? A, B, C, D?
Ghella [55]

Answer:

D. I've watched Jurassic park uwu

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2 years ago
How many moles are in 25 g KMnO4
Ronch [10]

Answer:

0.158 moles KMnO4

Explanation:

According to the Periodic Table,

K = 39.10 g/mol

Mn = 54.94 g/mol

O = 16.00 g/mol

KMnO4 = 39.10 g/mol + 54.94 g/mol + 4(16.00 g/mol) = 158.04 g/mol

25.0 grams KMnO4              1 mole

-----------------------------  x --------------------------  = 0.158 moles KMnO4

                                          158.04 grams

8 0
2 years ago
What’s the answer ?
Romashka-Z-Leto [24]

Answer:

45.3°C

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 82KPa

Initial temperature (T1) = 26°C

Final pressure (P2) = 87.3KPa.

Final temperature (T2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K.

Step 3:

Determination of the new temperature of the gas. This can be obtained as follow:

P1/T1 = P2/T2

82/299 = 87.3/T2

Cross multiply to express in linear form

82 x T2 = 299 x 87.3

Divide both side by 82

T2 = (299 x 87.3) /82

T2 = 318.3K

Step 4:

Conversion of 318.3K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 318.3K

T(°C) = 318.3 – 273

T(°C) = 45.3°C.

Therefore, the new temperature of the gas in th tire is 45.3°C

6 0
3 years ago
A vial is filled with room temperature water, and blue cold water has been placed at the bottom. A warm water bag sits next to t
MrRa [10]

Explanation:

In the context, a vial which is used in store medical samples is filled with water at room temperature. And the vial is kept on a cold water. Also a water bag containing warm water is kept near the vial.

The cold water kept at the bottom of the vial is having lower kinetic energy while warm water will have higher kinetic energy than the others. Since the water in the vial is at room temperature and it is in touch with the cold blue water, the water in the vial will loose or give its temperature to the cold blue water through conduction as well as convection process since temperature always flows from a hot body towards the cold body.

On the other hand, the warm water placed next tot he vial will give its temperature to the atmosphere.  

5 0
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