Question

If a concentration of 10 fluorescent molecules per μm2of cell membrane is needed to visualize a cell under the microscope, how many molecules of dye would be needed to visualize a single egg? Enter your answer in scientific notation rounded to two significant figures.

Answer 1

Answer : Total molecules that will be needed to visualize a single egg will be 78500 molecules of dye.

Explanation : As a single egg cell has an approximately diameter of 100 μm.

We can use this formula to calculate area of the cell membrane;

A = π $(100)^{2} / 4$;  

We can take π as 3.14 and we get;

A = 3.14 X $(100)^{2} / 4$  

Soving we get;

A =  7850 μ$m^{2}$  

Here we have to calculate the amount of dye molecules which will be needed for 10 fluorescent molecules / μ$m^{2}$  but;

here 1 μ$m^{2}$ = 7850 μ$m^{2}$ dye molecules.

Therefore, 10 fluorescent molecules will need;  

7850 X 10 = 78500 molecules of dye.

Therefore, the answer is 78500 molecules of dye.