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3 years ago

What occurs when the moon's shadow hits Earth or Earths shadow hits the moon

Chemistry

2 answers:

photoshop1234 [79]3 years ago

5 0

A lunar eclipse i think

dangina [55]3 years ago

3 0

Answer:

I believe you are looking for shadow eclipses :D

You might be interested in

What would be the most likely charge of an ion formed from an atom with the electron configuration: 1s22s22p63s2 (2 points) +1 -

Lady bird [3.3K]

+2 D. because this atom is magnesium and mag. has a charge of +2

3 0

3 years ago

Read 2 more answers

A 0.100 M oxalic acid, HO2CCO2H, solution is titrated with 0.100 M KOH. Calculate the pH when 25.00 mL of oxalic acid solution i

____ [38]

Answer:

pH = 4.09

Explanation:

molarity of oxalic acid in the solution

= 0.1 x 25 / (25 + 35)

= 0.0417 M

molarity of NaOH in the solution

= 0.1 x 35 / (25 +35)

= 0.0583 M

H2C2O4 + NaOH -------------------> NaHC2O4 + H2O

0.0417 0.0583 0 0

0 0.0166 0.0417

now second acid -base titration

NaHC2O4 + NaOH -------------------> Na2C2O4 + H2O

0.0417 0.0166 0 0

0.0251 0 0.0166 ---

now

pH = pKa2 + log [Na2C2O4 / NaHC2O4]

pH = 4.27 + log (0.0166 / 0.0251)

pH = 4.09

3 0

2 years ago

10 m3 of carbon dioxide is originally at a temperature of 50 °C and pressure of 10 kPa. Determine the new density and volume of

Dimas [21]

Answer : The new density and new volume of carbon dioxide gas is 0.2281 g/L and $7.2m^3$ respectively.

Explanation :

First we have to calculate the new or final volume of carbon dioxide gas.

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 10 kPa

$P_2$ = final pressure of gas = 15 kPa

$V_1$ = initial volume of gas = $10m^3$

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $50^oC=273+50=323K$

$T_2$ = final temperature of gas = $75^oC=273+75=348K$

Now put all the given values in the above equation, we get:

$\frac{10kPa\times 10m^3}{323K}=\frac{15kPa\times V_2}{348K}$

$V_2=7.2m^3$

The new volume of carbon dioxide gas is $7.2m^3$

Now we have to calculate the new density of carbon dioxide gas.

$PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}$

Formula for new density will be:

$\rho_2=\frac{P_2M}{RT_2}$

where,

$P_2$ = new pressure of gas = 15 kPa

$T_2$ = new temperature of gas = $75^oC=273+75=348K$

M = molar mass of carbon dioxide gas = 44 g/mole

R = gas constant = 8.314 L.kPa/mol.K

$\rho$ = new density

Now put all the given values in the above equation, we get:

$\rho_2=\frac{(15kPa)\times (44g/mole)}{(8.314L.kPa/mol.K)\times (348K)}$

$\rho_2=0.2281g/L$

The new density of carbon dioxide gas is 0.2281 g/L

5 0

2 years ago

3 natural chemicals a part of our life

Mademuasel [1]

Sodium chloride, methane gas and water

4 0

3 years ago

Read 2 more answers

Part A

KonstantinChe [14]

Answer:

The answer to your question is below

Explanation:

[H₃O⁺] = 2 x 10⁻¹⁴ M

pH = ?

Formula

pH = - log [H₃O⁺]

Substitution

pH = - log [2 x 10⁻¹⁴]

Result

pH = 13.7

[H₃O⁺] = ?

pH = 3.12

Formula

pH = - log [H₃O⁺]

Substitution

3.12 = - log [H₃O⁺]

$10^{-3.12} = [H_{3} O^{+}]$

Result

[H₃O⁺] = 7.59 M

7 0

3 years ago