<span>The number of x-intercepts that appear on the graph of the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)
Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0
Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2
(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2
(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
Answer:
x = -1
y = 4
Step-by-step explanation:
i believe this shape is a rhombus because the diagonals are perpendicular and bisectors, meaning m∡A = m∡B = m∡C = m∡D
so AC = CB = BC = DA
y + 1 = 2y - 3
1 = y - 3
4 = y
Plugging in 4 for 'y' means all sides are equal to 5
find x: 2x + 7 = 5
2x = -2
x = -1
PROBABILITY = 11 letters
VOWELS + T = A, E, I, O, U, Y, T = 7
P=7/11
I think it's answer choice a
Answer:
Step-by-step explanation:
Given
12.7, 22, 23.5, 24, 11, 22
Required
Determine the M.A.D
Start by calculating the Mean
In this case, n = 6
So:
Subtract the mean from each element
Take absolute value of the results above
The mean of the above gives the MAD
