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3 years ago

Help me plzzzzz 8th grade math

Mathematics

1 answer:

taurus [48]3 years ago

8 0

Answer:

1) y= 3/1x +4

2) y= 1/5x +3

3) y= 2/2x -2

4) y= -2/2x

5) y= -4/2x +8

6) y= 1/4x -7

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A triangle has angles that measure 46° and 61°. What is the measure of the third angle? A. 15° B. 73° C. 107° D. 134°

Nastasia [14]

The interior angles of a triangle need to be equal to 180°, so to solve this you need to figure out how many degrees you need to get 180°.

46 + 61 = 107

180 - 107 = 73

The measure of the third angle is B. 73°.

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3 years ago

Can the sides of a triangle have lengths 1, 3, and 4?

inysia [295]

Let's see.

We need to use a^2 + b^2 = c^2.

(1)^2 + (3)^2 = 4^2

1 + 9 = 16

10 DOES NOT EQUAL 16.

So, the answer to your question is no.

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What is (1.2 x 10^-2) x (3 x 10^5)

liraira [26]

Answer:

B. 3.6 x 10^3

Step-by-step explanation:

(1.2 x 10^-2) x (3 x 10^5)

When we multiply terms with powers , we multiply the factors out front and add the exponents

a * 10^b * c* 10^d = ac * 10^(b+d)

(1.2 x 10^-2) x (3 x 10^5) = (1.2* 3) * 10^(-2+5)

= 3.6 * 10 ^3

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3 years ago

If u+v+w=0, show that u x v = v x w = w x u.

Flauer [41]

Take the cross product of both sides of $\mathbf u+\mathbf v+\mathbf w=\mathbf0$ with $\mathbf u,\mathbf v,\mathbf w$ to generate a system of three simultaneous equations.

$(\mathbf u+\mathbf v+\mathbf w)\times\left\{\begin{matrix}\mathbf u\\\mathbf v\\\mathbf w\end{matrix}\right\}=\mathbf0\times\left\{\begin{matrix}\mathbf u\\\mathbf v\\\mathbf w\end{matrix}\right\}$
$\implies\begin{cases}\mathbf u\times\mathbf u+\mathbf u\times\mathbf v+\mathbf u\times\mathbf w=\mathbf0\\\mathbf v\times\mathbf u+\mathbf v\times\mathbf v+\mathbf v\times\mathbf w=\mathbf0\\\mathbf w\times\mathbf u+\mathbf w\times\mathbf v+\mathbf w\times\mathbf w=\mathbf0\end{cases}$
$\implies\begin{cases}\mathbf u\times\mathbf v+\mathbf u\times\mathbf w=\mathbf0\\\mathbf v\times\mathbf u+\mathbf v\times\mathbf w=\mathbf0\\\mathbf w\times\mathbf u+\mathbf w\times\mathbf v=\mathbf0\end{cases}$

since $\mathbf x\times\mathbf x=\mathbf0$ for any vector $\mathbf x$ .

Finally, use the fact that the cross product is anticommutative, i.e. $\mathbf x\times\mathbf y=-\mathbf y\times\mathbf x$ . The conclusion follows.

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Answer:

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