An ant needs to travel along a 20cm × 20cm cube to get from point A to point B. What is the shortest path he can take, and how l
ong will it be (in cm)?
1 answer:
Answer:
1. Along a diagonal, and then along an edge.
2. 48.28 cm.
Step-by-step explanation:
Assume points A and B are at diagonally opposite corners, as in the diagram below.
1. Shortest path
The shortest path is to go along the diagonal AC and continue along the edge CB.
2. Distance
The distance travelled is
d = AC + CB
According to Pythagoras,
AC² = AD² + CD² = 20² + 20² = 400 + 400 = 800
AC = √800 = 20√2
d = AC + CB = 20√ 2+ 20 ≈ 2 × 1.414 + 20 = 48.28 cm
The ant travels 48.28 cm.
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Answer:
The point of intersection of the system of equations is:
(x, y) = (-2, 1)
The correct system of equations intersect at point A in this graph will be:
Thus, the second option is correct.
Step-by-step explanation:
Given the point
- A (-2, 1)
Let us check the system of equations to determine whether it intersect at point A in this graph.
Given the system of equations
Arrange equation variable for elimination
so
so the system of equations becomes
Solve 7x = -14 for x
Divide both sides by 7
Simplify
For y - 4x = 9 plug in x = 2
Subtract 8 from both sides
Simplify
y = 1
Thus, the solution to the system of equations is:
(x, y) = (-2, 1)
From the attached graph, it is also clear that the system of equations intersects at point x = -2, and y = 1.
In other words, the point of intersection of the system of equations is:
(x, y) = (-2, 1)
Therefore, the correct system of equations intersect at point A in this graph will be:
Thus, the second option is correct.
