So ASA is angle side angle, and that means that if you prove that the side, and the side adjacent to that side and the angle between those two sides are all congruent to another triangle's sides and angle, the triangles are both congruent.
The AAS is angle angle side, or something, so say you have a triangle and you prove that two of its angles are congruent along with a side to another triangle's, then it's AAS. I understand where the confusion might be. I guess it's just a matter of what you state first in your proof?
Answer:
60 for both
Step-by-step explanation:
Since these angles are parallel, they are equal to each other :
6x = 5x + 10
Subtracting 5x from both sides gives us :
x = 10
Substituting this value back into both angles gives us
6x = 60
5x+10 = 60
Answer:
See below.
Step-by-step explanation:
1)
So we have:
This can be interpreted as:
"There exists a natural number <em>x</em> and an integer <em>y</em> such that x² is equal to y²."
2)
So we want even numbers are in the set of integers.
This is interpreted as:
"The set of even numbers (2n such that n is an integer) is in the set of integers"
Answer:
-4 is the correct answer to this problem
