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3 years ago

6

Mr. Herrera is going to

1 answer:

Mnenie [13.5K]3 years ago

7 0

Answer:

Mr. Herrera will hike 78 miles on 6th day.

Step-by-step explanation:

Given:

Number of miles Mr. Herrera will hike in 9 days = 117 miles

Total Number of days =9 days

Let us first find the number of miles he will hike in 1 day

By Using Unitary method we get,

Number of miles Mr. Herrera will hike in 1 days= $\frac{117} {9}=13\ miles$

We need to find miles hiked in 6th day.

Number of miles Mr. Herrera will hike on 6th day= Number of miles Mr. Herrera will hike in 1 days $\times$ Number of days = $13 \times 6 =78$

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Find the surface area of the prism

Pani-rosa [81]

Answer:

330

Step-by-step explanation:

The prism is a triangular prism

9 * (12 + 5 + 13) + (2 * 30)= 330

30 being the base area

4 0

3 years ago

Read 2 more answers

Find the geometric mean of 275 and 11 275/x=x/11 x^2= 3025 x=sq rt 3025 now I'm not sure what to do.

Bogdan [553]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
you got it
<span>except keep going to get </span>
<span>x = ±√3025 </span>
<span>x = ± 55 </span>

<span>check: </span>
<span>275 , 55, 11 </span>
<span>is 55/275 = 11/55 ? YES </span>
<span>is -55/275 = 11/=55 ? YES</span>

6 0

3 years ago

How do you find 79% of 32

liubo4ka [24]

Convert 79% to a decimal which is .79

Then you multiply .79 by 32 which is 25.28

Your answer is 25.28

5 0

3 years ago

the perimeter of an isosceles triangle in which the equal sides measures 12cm each and third side is 8cm_____. please show the w

KiRa [710]

Answer:

The perimeter of the isosceles triangle is 32 centimeters

Step-by-step explanation:

<em>The perimeter of any figure is </em><em>the sum of the lengths of outline sides</em>

Let us use this fact to solve our question

∵ The perimeter of the triangle is the sum of the lengths of its 3 sides

∵ The triangle is an isosceles triangle

∵ The length of each two equal sides is 12 centimeters

∵ The length of the third side is 8 centimeters

→ Add the lengths of the 3 sides

∴ The perimeter of the triangle = 12 + 12 + 8

∴ The perimeter of the triangle = 32 centimeters

∴ The perimeter of the isosceles triangle is 32 centimeters

8 0

3 years ago

If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.

oksian1 [2.3K]

Answer:

$NK = 15$

$JL = 26$

$KL = 19.85$

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

Step-by-step explanation:

Given

$MK = 30$

$NL = 13$

$\angle MKL = 41$

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

$NK = \frac{1}{2} * MK$

$NK = \frac{1}{2} * 30$

$NK = 15$

Solving (b): JL

JL is a diagonal, and it is twice of NL.

$JL = 2 * NL$

$JL = 2 * 13$

$JL = 26$

Solving (c): KL

To solve for KL, we consider triangle KNL where:

$\angle KNL = 90$

and

$KL^2 = NL^2 + NK^2$

$KL^2 = 13^2 + 15^2$

$KL^2 = 394$

$KL = \sqrt{394$

$KL = 19.85$

Solving (d - h):

To do this, we consider triangle JKN

$\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90$ -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

$\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41$

Similarly:

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41$

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49$

So:

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = \angle MLJ + \angle JLK$

$\angle MLK = 49 + 41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

5 0

3 years ago