Answer:
560880
Step-by-step explanation:
THERE
When you plug the equation into a graphing calculator the x-intercept is -5
Or you can set the equation equal to 0 and solve for x.
X = -3.
The distance from p(-9, 0, 0) is
d = sqrt((x+9)^2 + y^2 + z^2)
The distance from q(3,0,0) is
d = sqrt((x-3)^2 + y^2 + z^2)
Let's set them equal to each other.
sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
Square both sides, then simplify
(x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
18x + 81 = - 6x + 9
24x + 81 = 9
24x = -72
x = -3
So the desired equation is x = -3 which defines a plane.
Well, this is a Pythagorean theorem problem. A^2 + B^2 = C^2, where C^2 is equal to the hypotenuse. 8 squared equals 64, so c^2 = 64 cm. The other leg can be represented by A^2, which is 36 cm. 36 + ? = 64. 64 - 36 = 28, so B^2 equals 28. Now, to find the measurement of the other leg, we need the square root of 28. The square root of 28 is 5.3 cm.
Your final answer is 5.3 cm.
Answer:
-2 °F > -6 °F
Step-by-step explanation:
-2 is to the right of -6 on the number line, so is the greater of the two values. The temperature has to go up from -6 to get to -2. Thus, ...
-2 °F > -6 °F