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NARA [144]
4 years ago
5

How many complex roots does the polynomial equation have? 5x^3−4x+1=0

Mathematics
1 answer:
OverLord2011 [107]4 years ago
3 0

Answer:

It has zero complex roots.  The roots are:  0.72360679774998,  -1 and 0.27639320225002   http://www.1728.org/cubic.htm

Step-by-step explanation:


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find the solution to the system. write your solution as an ordered pair (x,y) with no spaces, no solution or infinitely many 2x-
Kitty [74]

Answer:

(-8,4)

Step-by-step explanation:

Given: 2x-3y=-28 and x+6y=16

solve for a variable and then substitute back into other equation

x + 6y = 16

x = 16 - 6y; now use this in the other equation

2x - 3y = -28; substitute into x

2(16 - 6y) - 3y = -28; distribute 2

32 - 12y - 3y = -28; combine y's

32 - 15y = -28; isolate 15y

32 + 28 = 15y; add the numbers

60 = 15y; divide by 15

y = 4

Now use this to plug into other equation

x + 6y = 16; y=4

x + 6(4) = 16;

x + 24 = 16; subtract 24 from both sides

x = -8

4 0
3 years ago
The kerwoods went out to eat at Chili's if there's a bill if they're bill was 58.16 they get in they gave their serve a 15% tip
cestrela7 [59]
8.724 15% of 58.16 is 8.724$
5 0
3 years ago
Read 2 more answers
Which data type is variable 'a' as per below code?(numeric/non-numeric) Dim a as integer a=10 for grade 7 Computer
Lorico [155]

Answer:

The answer is "numeric".

Step-by-step explanation:

The Dim keyword is used in Visual Basic which is used to establish the dependent variable and other information such as the code that the variable may access the variables, computer utilizes the statement Dim. The dimensions are brief and then used to define variables. The Dim statement is placed just after sub definition only at the start of a VBA module (short for Subroutine).The variable to hold an integer value is seen in the above example.

8 0
3 years ago
I just need a quick small response for this.
Degger [83]

Answer:

the process of isolating a variable in these literal equations is similar to solving a one-step equation because after isolating a variable you solve the rest of the equation,it is different from solving a one-step equation because it is more than one step so it takes longer to solve

5 0
3 years ago
Let f(x) = 13 - |2x+ 1|. Find all x for which f(x) less than or equal to 14
Art [367]

Answer:

x \leqslant -1\: or \: x  \geqslant  - 1

Step-by-step explanation:

The given function is

f(x) = 13 -  |2x + 1|

We want to find all values of x for which:

f(x) is greater than or equal to 14.

This implies;

13 -  |2x + 1|  \geqslant 14

Subtract 13 from both sides;

-  |2x + 1|  \geqslant 14 - 13

|2x + 1|  \geqslant - 1

By definition of the absolute value function,

- (2x + 1) \geqslant  - 1 \: or \: (2x + 1) \geqslant  - 1

Divide through the first inequality and and reverse the inequality sign:

2x + 1 \leqslant -1 \: or \: 2x + 1 \geqslant  - 1

2x \leqslant -1  - 1 \: or \: 2x  \geqslant  - 1  - 1

2x \leqslant -2 \: or \: 2x  \geqslant  - 2

x \leqslant -1\: or \: x  \geqslant  - 1

8 0
4 years ago
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