23.4 ft
I know this is late but hope it helps!
Answer:3/
Step-by-step explanation:
ax² + bx + c = 0
x = (-b ± √(b² - 4ac))/2a
First, rewrite the first equation so that the first coefficient is 1. Divide everything by a.
(ax² + bx + c = 0)/a =
x² + (b/a)x + (c/a) = 0
Isolate (c/a) by subtracting (c/a) from both sides
x² + (b/a)x + (c/a) (-(c/a) = 0 (- (c/a)
x² + (b/a)x = 0 - (c/a)
Add spaces
x² + (b/a)x = -c/a
Take 1/2 of the middle term's coefficient and square it. Remember that what you add to one side, you add to the other.
x² + (b/a)x + (b/2a)² = -c/a + (b/2a)²
Simplify the left side of the equation.
x² + (b/a)x + (b/2a)² = (x + (b/2a))²
(x + b/2a))² = ((b²/4a²) - (4ac/4a²)) -> ((b² - 4ac)/(4a²))
Take the square root of both sides of the equation
√(x + b/2a))² = √((b²/4a²) - (4ac/4a²))
x + b/(2a) = (±√(b² - 4ac)/2a
Simplify. Isolate the x.
x = -(b/2a) ± (∛b² - 4ac)/2a = (-b ± √(b² - 4ac))/2a
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Answer:
The measure of angle MNP is
m ∠ MNP = (x - y)/2
Explanation:
The image attached shows the figure corresponding to this question.
The angle MNP, which is also the angle LNP, is formed by the intersection of a secant and a tangent to a circle.
Then, you can use the theorem:
the angle formed by a secant and a tangent to a circle that intersect outside the circle is half the difference of the major arc minus the minor arc.
The major arc formed is identified with the letter x and the minor arc is identified with the letter y. Thus, the measure of the angle MNP is half the difference x - y:
m ∠ MNP = (x - y)/2
Brainliest please
Answer:
3.) D
4.) B
Step-by-step explanation:
