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Crank
3 years ago
8

What the constant rate of change?

Mathematics
1 answer:
lozanna [386]3 years ago
6 0
For straight lines the constant rate of change(slope) is a constant(always the same) For every unit moved on the x-axis two more are moved on the y-axis
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15 - 3k = 10(k-5) <br> Can someone please answer this
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Answer:

k = 5

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

15 - 3k = 10(k - 5)

<u>Step 2: Solve for </u><em><u>k</u></em>

  1. Distribute 10:                              15 - 3k = 10k - 50
  2. Add 3k to both sides:                15 = 13k - 50
  3. Add 50 to both sides:                65 = 13k
  4. Divide 13 on both sides:            5 = k
  5. Rewrite:                                       k = 5

<u>Step 3: Check</u>

<em>Plug in k into the original equation to verify it's a solution.</em>

  1. Substitute in <em>k</em>:                    15 - 3(5) = 10(5 - 5)
  2. Subtract:                              15 - 3(5) = 10(0)
  3. Multiply:                               15 - 15 = 0
  4. Subtract:                              0 = 0

Here we see that 0 does indeed equal 0.

∴ k = 5 is a solution of the equation.

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The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.


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