Find an equation for the line that passes through the points (4,3) and (-6,5)

Mathematics

1 answer:

mixer [17]3 years ago

7 0

Answer:

y = -1/5x + 19/5 or

x + 5y = 19.

Step-by-step explanation:

The slope of the line (m) = (5-3) / (-6-4)

= -1/5.

Using the point-slope form of the equation of a line:

y - y1 = m(x - x1) m = -1/5. x1 = 4 and y1 = 3 , so:

y - 3 = -1/5(x - 4)

y - 3 = -1/5x + 4/5

y = -1/5x + 19/5 which is the equation in slope-intercept form.

Converting to standard form ( multiplying by 5):

5y = -x + 19

x + 5y = 19.

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