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3 years ago

A circular garden has a diameter of 6 yards.What is the area of the garden. Use 3.14

Mathematics

2 answers:

emmainna [20.7K]3 years ago

8 0

Answer:

28.26 yd^2

Step-by-step explanation:

A = 3.14 • r^2

Radius is half of the diameter, so 3.

A = 3.14 • 3^2

A = 3.15 • 9

A = 28.26 yd^2

Anastaziya [24]3 years ago

4 0

Answer: The area of the garden is 28.26

Step-by-step explanation:

1. Divide the diameter in half, that gives you the radius, in this case: 3

2. Use the formula for finding the area with the radius: A= π r², and use 3.14 instead of pi. Multiply 3.14 by 3²

3. You should get 28.26 as your answer.

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Stu hiked a trail at an average rate of 3 miles per hour. He ran back on the same trail at an average rate of 5 miles per hour.

Andrews [41]

3t = 5(3-t)
3t = 15 - 5t
3t + 5t = 15
8t = 15
t = 15/8
t = 1 7/8

7/8 * 60 mins = 52.50 minutes

t = 1 hour and 52.5 minutes

It took Stu 1 hour and 52.5 minutes to hike the trail one way.

3 0

3 years ago

Read 2 more answers

You are paid 1.5 times your normal hourly rate for each hour you work over 30 hours in a week. You work 34 hours this week and e

natulia [17]

Answer: $15.94

Step-by-step explanation:

Let r be your rate you get paid per hour normally. Let's set up this equation.

(30 * r) + 4(1.5 * r) = 573.83

30r + 6r = 573.83

36r = 573.83

r = 15.94 (rounded)

You get paid $15.94 hourly.

8 0

1 year ago

Sally lives in City A and works for the department of transportation. She needs to inspect the weigh stations in each of four di

galben [10]

Answer:

She can visit the cities in 192 ways

Step-by-step explanation:

If Sally starts from city A and after going to 4 cities she returns to home,

then that can be in 4! = 24 ways. (permutation of 4 distinct objects)

If between the time she visits cities, she comes home once,

then cities can be visited in,

$4! \times 3_{C_{1}}$ = 72 ways. (permutation of 4 distinct objects and choosing 1 gap among the 3 )

If between the time she visits cities, she comes home twice,

then cities can be visited in,

$4! \times 3_{C_{2}}$ =72 ways. (permutation of 4 distinct objects and finding 2 gaps among the 3)

If between the time she visits cities, she comes home thrice,

then cities can be visited in,

$4! \times 3_{C_{3}}$ = 24 ways. (permutation of 4 distinct objects and choosing 3 gaps among the 3)

Now, she can't come home more than thrice in between the time she visits cities (since there are 4 cities to visit only)

So, the number of ways she can visit cities = (24+ 72 + 72 + 24)

= 192

6 0

3 years ago

PLEASE HELP AND EXPLAIN STEP BY STEP.

SIZIF [17.4K]

A. The two listed added up will be 180 degrees.

5x - 57 + 3x + 5 = 180

8x - 52 = 180

8x - 52 + 52 = 180 + 52

8x = 232

x = 29

B. The two listed added up will be 180 degrees.

2x + 4x + 150 = 180

6x + 150 = 180

6x + 150 - 150 = 180 - 150

6x = 30

x= 5

Can I get brainlyist

8 0

3 years ago

exam p A drawer contains four pairs of socks, with each pair a different color. One sock at a time is randomly drawn from the dr

Marta_Voda [28]

Answer:

The probability that the maximum number of draws is required is 0.2286

Step-by-step explanation:

The probability that the maximum number of draws happens when you pick <em>different colors in the first four pick</em>.

Assume you picked one sock in the first draw. Its probability is 1, since you can draw any sock.

In the second draw, 7 socks left and you can draw all but the one which is the pair of the first draw. Then the probability is $\frac{6}{7}$

In the third draw, 6 socks left and you can draw one of the two pair colors which are not drawn yet. Its probability is $\frac{4}{6}$

In the forth draw, 5 socks left and only one pair color, which is not drawn. The probability of drawing one of this pair is $\frac{2}{5}$

In the fifth draw, whatever you draw, you would have one matching pair.

The probability combined is 1× $\frac{6}{7}$ × $\frac{4}{6}$ × $\frac{2}{5}$ ≈ 0.2286

5 0

3 years ago