B - Sediment . Many layers of sediment slowly built up into a rock which turn into a fossil .
<span>The radioactive uranium decays into its daughter product, lead. It would do this in magma as well, as nuclear decay depends on forces within the atom, not on the phase of the material in which the atom is a part.</span>
The molarity of the potassium hydroxide required to neutralize 60.0 mL of 0.0100 M H3PO4 is 0.02M.
<h3>How to calculate molarity?</h3>
The molarity of a solution can be calculated using the following formula:
CaVa = CbVb
Where;
- Ca = concentration of acid
- Cb = concentration of base
- Va = volume of acid
- Vb = volume of base
60 × 0.0100 = 30 × Cb
0.6 = 30Cb
Cb = 0.6/30
Cb = 0.02M
Therefore, molarity of the potassium hydroxide required to neutralize 60.0 mL of 0.0100 M H3PO4 is 0.02M.
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Answer:
The nucleus of an atom is made up of a dense ball
of <u>protons</u> and <u>neutrons</u> surrounded by <u>electrons.</u>
Explanation:
We know that an atom consist of electrons, protons and neutrons. Neutrons and protons are present inside the nucleus while electrons are present out side the nucleus. Electron has a negative charge and is written as e⁻. The mass of electron is 9.10938356×10⁻³¹ Kg . While mass of proton and neutron is 1.672623×10⁻²⁷Kg and 1.674929×10⁻²⁷ Kg respectively.
Symbol of proton= P⁺
Symbol of neutron= n⁰
The number of electron or number of protons are called atomic number while mass number of an atom is sum of protons and neutrons. The umber of protons and electrons are always equal to make the atom electrically neutral and when an atom loses its valance electron the number of protons increases and thus positive charge increased and atom form cation.
Answer: The concentration of unknown sample is 1.8 mg/ml
Explanation:
According to the dilution law,
where,
= concentration of stock solution = ?
= volume of stock solution = 0.25 ml
= concentration of diluted solution = 0.45 mg/ml
= volume of diluted solution = (0.25+0.75) ml = 1.00 ml
Putting in the values we get:
Therefore, concentration of unknown sample is 1.8 mg/ml