Answer:
0.11 M
Explanation:
The computation of molarity of the CH3COOH solution is shown below:-

Where,
= Molarity of LioH = 0.0175
= Volume of LioH = 18.5 ml
= Volume of CH3COOH = 29.4 ml
Now, we will put the values into the formula

Which gives result
= 0.011 M
Therefore for computing the molarity of the CH3COOH solution we simply applied the above formula.
20 g is the answer to make it a saturated solution
Answer is: 25.84 milliliters of sodium metal.
Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.
d(Na) = 0.97 g/mL; density of sodim.
m(NaOH) = 43.6 g; mass of sodium hydroxide.
n(NaOH) = m(NaOH) ÷ M(NaOH).
n(NaOH) = 43.6 g ÷ 40 g/mol.
n(NaOH) =1.09 mol; amount of sodium hydroxide.
From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).
n(Na) = 1.09 mol.
m(Na) = 1.09 mol · 23 g/mol.
m(Na) = 25.07 g; mass of sodium.
V(Na) = m(Na) ÷ d(Na).
V(Na) = 25.07 g ÷ 0.97 g/mL.
V(Na) = 25.84 mL.
A.) Most reactive non-metals