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Viktor [21]
3 years ago
7

A metamorphic rock can also be thought of as a rock that changes. What causes the rock to change?

Chemistry
2 answers:
Nana76 [90]3 years ago
5 0

Answer:

its ethier b or c

Explanation:

Eduardwww [97]3 years ago
4 0

Answer:

I think it is B

Explanation:

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Which of the following is a limitation of Bohr's model?
Murljashka [212]

Answer:

 The answer is:

The first option

Explanation:

6 0
3 years ago
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6 0
3 years ago
What is the concentration of magnesium bromide, in ppm, if 133.4 g MgBr2 dissolved in 1.84 L water. Then solve for the bromine c
Serhud [2]

Answer: 0.0725ppm

Explanation:

133.4g of MgBr2 dissolves in 1.84L of water.

Therefore Xg of MgBr2 will dissolve in 1L of water. i.e

Xg of MgBr2 = 133.4/1.84 = 72.5g

The concentration of MgBr2 is 72.5g/L = 0.0725mg/L

Recall,

1mg/L = 1ppm

Therefore, 0.0725mg/L = 0.0725ppm

7 0
3 years ago
A sample of an unknown compound with a mass of 0.847 g has the following composition: 50.51 % fluorine and 49.49 % iron. When th
sergejj [24]

Answer: 0,4278g of F and 0,4191g of Fe

Explanation: it's possible to calculate the mass of each element by multiplying the percentage (decimal) of the element by the mass of the compound.

For Fluorine (F)

0,847g * 0,5051 = 0,4278g of F

For iron (Fe)

0,847 * 0,4949 = 0,4191g of Fe

This is determined because even when the compound is decomposed, due to conservative law of mass, the decomposition process do not affect the amount of matter, so the mass of the elements remain even if they are separated from the original molecule.

At the end, the sum of the elements masses should be the total mass of the compound.

4 0
3 years ago
Read 2 more answers
26 grams of CO2 to moles
neonofarm [45]
First, find out how many grams are in one mole of CO2(the two oxygen atoms means you need to multiply oxygen’s amu by 2,then add whatever carbon’s amu is to that). Then divide 26 grams by that number and that will be your moles. There are only two significant figures, so round your answer correctly.
4 0
3 years ago
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