Answer:
ΔG°′ = 1.737 KJ/mol
Explanation:
The reaction involves the transfer of two electrons in the form of hydride ions from reduced coenzyme Q, CoQH₂ to fumarae to form succinate and oxidized coenzyme Q, CoQ.
The overall equation of reaction is as follows:
fumarate²⁻ + CoQH₂ ↽⇀ succinate²⁻ + CoQ ; ΔE∘′=−0.009 V
Using the equation for standard free energy change; ΔG°′ = −nFΔE°′
where n = 2; F = 96.5 KJ.V⁻¹.mol⁻¹; ΔE°′ = 0.009 V
ΔG°′ = - 2 * 96.5 KJ.V⁻¹.mol⁻¹ * 0.009 V
ΔG°′ = 1.737 KJ/mol
Temperature does not change, remains 264 K
<h3>Further explanation</h3>
Given
V₁= 1.2 L
P₁ = 1.8 atm
T₁ = 264
Required
The new temperature
Solution
The volume was doubled = 2V₁ = 2 x 1.2 = 2.4 L(V2)
The pressure was halved = 0.5P₁ = 0.5 x 1.8 = 0.9 atm(P2)
Combined gas law :
P₁V₁/T₁=P₂V₂/T₂
Input the value :
We need to make sure that the pressure is in the same units.
let's convert the atm to mmHg. remember that 1 atm= 760 mmHg
1.03 atm (760 mmHg/ 1 atm)= 783 mmHg
to find the pressure of the gas, you just need to subtract the values
pressure of gas= 783 - 305 = 478 mmHg
The atmosphere contains the air we breathe
Answer:
When the average kinetic energy of the molecules goes up (a rise in temperature), the average speed of the molecules increases. And lower average kinetic energy of the molecules means they have lower speed. When heat (energy) goes into a substance one of two things can happen:
Explanation:
If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. ... If the gas volume is decreased, the container wall area decreases and the molecule-wall collision frequency increases, both of which increase the pressure exerted by the gas (Figure 1). Avogadro's law.