Answer:
Counterclockwise rotation about the origin by 90 degrees followed by reflection about the y-axis
.
Step-by-step explanation:
The shape is moved to the opposite quadrant of the second shape then flied directly onto the second shape.
C and D
150(1+2.5) and 150(3.5)
Answer:
the probability that a code word contains exactly one zero is 0.0064 (0.64%)
Step-by-step explanation:
Since each bit is independent from the others , then the random variable X= number of 0 s in the code word follows a binomial distribution, where
p(X)= n!/((n-x)!*x!*p^x*(1-p)^(n-x)
where
n= number of independent bits=5
x= number of 0 s
p= probability that a bit is 0 = 0.8
then for x=1
p(1) = n*p*(1-p)^(n-1) = 5*0.8*0.2^4 = 0.0064 (0.64%)
therefore the probability that a code word contains exactly one zero is 0.0064 (0.64%)
Answer:
z = 10
Step-by-step explanation:
First apply multiplication to inside the parenthesis:
2(z+5) = 2z + 10
5(z+ 2) = 5z + 10
10(z − 1) = 10z - 10 now write the full equation
2z + 10 + 5z + 10 = 10z - 10 add like terms
7z + 20 = 10z - 10 transfer like terms to the same side of the equation
20 + 10 = 10z - 7z
30 = 3z divide both sides by 3
10 = z
Answer:
The first one, fifth one, and final one!
