Here's some code that might help, assuming that you are using JavaScript.
e = "Hello"
if(e === "Hello"){
alert(":D")
}else{
console.log("Um.")
}
I think that the answer is curly brackets.
Answer:
Check the explanation
Explanation:
#include <iostream>
#include <iomanip>
using namespace std;
int getIQ(); // return the score
void printEvaluation(int);
int main()
{
int IQ = 0;
IQ = getIQ();
printEvaluation(IQ);
return 0;
}
int getIQ()
{
int score = 0;
cout << "Please enter your IQ Score to receive your IQ Rating:\n";
cin >> score;
return score;
}
void printEvaluation(int aScore)
{
cout << "IQ Score: " << aScore << " IQ Rating: ";
if (aScore <= 100)
{
cout << "Below Average\n";
}
else if (aScore <= 119)
{
cout <<"Average\n";
}
else if (aScore <= 160)
{
cout << "Superior\n";
}
else if (aScore >= 160 )
{
cout << "Genius\n";
}
}
Answer:
FALSE
Explanation:
Because C1 and C2 implement the same interface, they both implement whichIsIt. The variable c is known as a polymorphic variable, meaning that it can change from being an C1 to a C2. So, the message c.whichIsIt( ); may invoke C1's whichIsIt or C2's whichIsIt. This can only be known at runtime.
